Here's the simplest thing I can think of to get roughly 600mV, you'll have to play with the resistor a bit probably. I want to get enough drive off 5V to get 600mV, but not toast the diode if the supply jumps to 20V
I'm looking to convince a qualcom usb quick charge device to output 12v, to do this it needs to sense 0.6v on the plus and minus data lines https://blog.oxplot.com/quickcharge/
I want to build a circuit which will take power from the normal 5v usb socket and output 0.6v to the data lines
Well, if you use wrong information to solve a problem that does not exist you might end up running around in circles. According to the USB specifications the resistors provided in a conform charger provide either the voltages required for Apple products or those for all other (normal) devices. If a conform phone and conform charger won't be able to provide the specified charging current than in 99.95% of cases the USB is to blame. But no matter what you mess up on the data lines the charger will always and only output 5V. To make it provide 12V you need to modify the electronics inside - those responsible to drive the output circuit. If you need 12V then do yourself a favour and buy a 12V adapter/charger.
The Vbus is used to determine the charging current on all USB2 systems, as per USB 3 specification all fast charge enabled devices communicate over Vbus with the charger to set the charging voltage. So it is not as simpla as with USB2 where you just put the correct resistors onto the unused datalines.
Comments
Best Answer 4 years ago
For the doubters out there
http://www.mouser.com/new/Power-Integrations/Power...
Here's the simplest thing I can think of to get roughly 600mV, you'll have to play with the resistor a bit probably. I want to get enough drive off 5V to get 600mV, but not toast the diode if the supply jumps to 20V
Answer 4 years ago
Sorry for the late reply, thank you for your answer.
4 years ago
What for ? Making a regulator do it isn't too hard, but knowing why might let us give you a better answer
Answer 4 years ago
I'm looking to convince a qualcom usb quick charge device to output 12v, to do this it needs to sense 0.6v on the plus and minus data lines
https://blog.oxplot.com/quickcharge/
I want to build a circuit which will take power from the normal 5v usb socket and output 0.6v to the data lines
Answer 4 years ago
Well, if you use wrong information to solve a problem that does not exist you might end up running around in circles.
According to the USB specifications the resistors provided in a conform charger provide either the voltages required for Apple products or those for all other (normal) devices.
If a conform phone and conform charger won't be able to provide the specified charging current than in 99.95% of cases the USB is to blame.
But no matter what you mess up on the data lines the charger will always and only output 5V.
To make it provide 12V you need to modify the electronics inside - those responsible to drive the output circuit.
If you need 12V then do yourself a favour and buy a 12V adapter/charger.
Answer 4 years ago
If you read the spec of qualcomm quick charge you will find it can output up to 20V over usb its not limited to 5V at all
Answer 4 years ago
Then check the USB 3 specifications to work out how to get the 20V.
http://www.usb.org/developers/docs/
The Vbus is used to determine the charging current on all USB2 systems, as per USB 3 specification all fast charge enabled devices communicate over Vbus with the charger to set the charging voltage.
So it is not as simpla as with USB2 where you just put the correct resistors onto the unused datalines.
Answer 4 years ago
You'd do that with resistors ! Or a resistor and a single forward biased diode.
Answer 4 years ago
Thanks Steve!
Could you point me to some circuit examples maybe something explaining what components values I would need and how to wire them up?
Answer 4 years ago
+1
4 years ago
Step down voltage converter. Search for one on eBay.
Answer 4 years ago
Hi Yonantan,
I have looked I can't find any which go down to 0.6V
Answer 4 years ago
http://www.ebay.com/sch/i.html?_from=R40&_trksid=m... I think.
Read what everything says, I didn't make sure...