How do i key in a 4x4 matrix keypad input into arduino and control the brushless motor? Answered

here's my code... but i have a new problem... the code only can read the any value between 103 till 180. Knowing that servo library have a value of 0-180... i tried to input any value from 0-102... the code does not read it and no spinning of the motor... i was wondering you can guide me on that..Here's my code

#include "Keypad.h"

#include <LiquidCrystal.h>

#include <Servo.h>

// initialize the library with the numbers of the interface pins

LiquidCrystal lcd(A0,A1,A2,A3,A4,A5);

Servo myservo;

const byte ROWS = 4; //four rows

const byte COLS = 3; //four columns

char keys[ROWS][COLS] =

{{'1','2','3'},

{'4','5','6'},

{'7','8','9'},

{'*','0','#'}

};

byte rowPins[ROWS] = {9,8,7,6}; //connect to the row pinouts of the keypad

byte colPins[COLS] = {5,4,3}; //connect to the column pinouts of the keypad

int count=0;

Keypad keypad = Keypad( makeKeymap(keys), rowPins, colPins, ROWS, COLS );

void setup()

{

Serial.begin(9600);

lcd.setCursor(0,0);

lcd.print("Servo");

lcd.begin(16,2);

myservo.attach(11);

}

void loop()

{

static char buffer[4];

static byte i = 0;

char key = keypad.getKey();

// i < 3: prevent buffer overflow

if ('0' <= key && key <= '9' && i < 3)

{

buffer[i] = key;

++i;

lcd.print(key);

}

else if (key == '#' && i > 0)

{

buffer[i] =0; // null-terminate buffer

Serial.print(buffer);

int value = atoi(buffer);

myservo.write(value);

i = 0;

}

}

I tried your code for my stepper motor project I couldn't display the "value" in my oled and what i did was to save "value" to and int x x=value; and then save x to another int a for example and send 'a' to my display

It works fine

The terminating condition for your buffer collection is wrong. It will ONLY accept three numbers, not one or two.

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