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Is it possible to make a solar powered diffuser jewelry that emits steam with miniLED light Answered

I have come across instructables that I wanted to combine: the homemade solar cell using household materials which can be found here, the LED jewelry that can also be found here, and lastly, doing the diffuser procedure which is actually just adding the essential oil on the boiling water. it's like making a ministeam boiler but worn as accessory. I need help with this? Thanks! I think it would involve calculating volts converting the equivalent solar cell measurements to the most smaller measurements as possible. And also how long would the solar cell can be able to sustain and how many volts do I need to reach boiling point? Thanks! I will be updating as soon as I can gather and connect these things. Accdg. To my research, to water to reach boiling point, a 1kg water = 1,200 joules/min. Or 1,600 watts. I wanna know how many watts or volts in order to boil a 1ml water?


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Jack A Lopez
Jack A Lopez

1 year ago

This is certainly imaginative, and you seem to be combining features of this idea from different sources; i.e. "homemade solar cell", "LED jewelry", and "diffuser... just adding the essential oil on the boiling water."

I noticed for the first two of those, you use the words, "can be found here," but I am not sure what you mean by that, although two possibilities come to my mind. One is you intended to connect some URLs to those, so as to point to them directly. The other possibility is, "here," means, "at Instructables.com," meaning instructables on those topics are here, somewhere, and presumably easy to find.

If you have some specific 'ibles, or other web pages, you want to point out to persons reading this, well, you know, links are the best way to do that.

Regarding the topic of boiling water, I think a good figure of merit,


for water boiling appliances, or generally for any kind of heating appliance, is its total dissipated power, divided by its surface area.

The units I am going to use for this are watts per square centimeter.

Although, before getting into that, I wanted to point out the curious fact that water, or other volatile liquids, spontaneously turn into vapor.

For example, a few grams of water sitting in a dish, at room temperature, will evaporate by itself, in some amount of time.

Also a process like this can be sped up by simple tricks. A paper towel added to the same dish of water, will help the water evaporate faster, by increasing its surface area.

Back to the topic of heating appliances, I think typical power densities for heating appliances are in the range of about 1 to 10 watts per square centimeter.

As an example, consider a typical electric hot plate,

If such a device were pushing 500 watts, through a surface of 100 cm^2, i.e. a circle with diameter 11.3 cm (or 4.44 inches), then the power density for this would be (500 W)/(100 cm^2) = 5.0 W/cm^2

Conveniently, the power density of sunlight, can be measured with the same units.


"At most about 75% of the solar energy actually reaches the earth's
surface,[16] as even with a cloudless sky it is partially reflected and
absorbed by the atmosphere. Even light cirrus clouds reduce this to 50%,
stronger cirrus clouds to 40%. Thus the solar energy arriving at the
surface can vary from 550 W/m² with cirrus clouds to 1025 W/m² with a
clear sky."

By the way, 1000 watts per square meter is an often used, good round number, corresponding to full intensity sunlight, on the Earth's surface, on a clear day.

Converting that number to watts per square centimeter, gives:

(1000 W/ m^2)* (1 m^2/10000 cm^2) = 0.10 W /cm^2

which is smaller than the power density for a good water boiler by a factor of about 10 to 100.

I think the easiest way to concentrate solar power, is just using optics, e.g. a big lens, or a parabolic mirror.

If you want to do it using photovoltaics (i.e. solar cells) and electric heating elements, you are going to lose about 90% of your power, since typical PV cells have around 10% efficiency, at converting light to electricity.

As a consequence of this, the ratio in areas, between your light collector and your boiler, could be as high as 1000 to 1. E.g. a solar panel with area 32 cm by 32 cm, square, and a boiler with area around 1 cm^2.

I mean, I think it would be very challenging to make both the solar panel, and the electric boiler, at "jewelry scale", which is to say both with dimensions measured in just a few cm.

Although, I recall seeing a novelty, parabolic reflector cigarette lighter, with dimensions of about 10 cm diameter, and I think I have one around here somewhere, although I don't remember where I put it. It worked, on clear days, without too much wind. I am sure it could be adapted to boiling small amounts of water.

However I am not sure if it is the size, and shape, you would consider as jewelry. Um... unless you and Flavor Flav have similar tastes in jewelry.

Does Wikipedia have a picture of him wearing that wall-sized clock, on a chain around his neck? Ha! Yes they do, at the time of this writing.

I mean I don't want to disparage Flavor Flav's taste in bling, or yours if you also like wearing things the size of pots and pans, on your neck or wrist.

I am going to attach a picture of one of those parabolic mirror cigarette lighters. You can find those wherever novelties like that are sold, like Flea-buy or Scam-a-zon, if you cannot find one at a local store that sells camping, survival, or outdoorsy stuff.

Also if you actually want to pursue electric heating elements, there are people out there who build their own "electric cigarettes, aka e-cigs" and "vaporizers", and I think if you look into those you will find power densities similar to what I have mentioned here, i.e. around 1 to 10 watts per square centimeter of heater. Of course I have already warned you, the size of electric PV panel needed to power it might be uncomfortably large.


1 year ago

Don't really know why you need boiling water, wouldn't bea ultrasonic mister provide enough "steam" ?
Or just some sanded acrylic as a diffusor?