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Making new tesla? Answered

Will 1280' (feet) coil the, 26 awg wire

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iceng

Best Answer 6 years ago

Wat dia in feet ?

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icengwiccakingkamui

Answer 6 years ago

Then one coil of #26 awg wire diameter o.015940" is a o.00133' added to the tube  results in a true o.33466' diameter which multiplied by Pi uses 1.05137' of wire per turn.

A 1280' length of wire divided by 1.0514' will allow 1217 turns of wire and
multiplied by wire diameter will need tube at least as high as 1.62' or 19.5"..
This assumes a perfect winding.  In practice add 12% slop to 1.82' or  21.8" tube height.

A.

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wiccakingkamuiiceng

Answer 6 years ago

Did you say I'll only get half of it done with this spool

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icengwiccakingkamui

Answer 6 years ago

1/3' dia =o.33333333333333' + o.00133 = o.33466' dia × 3.14159 = 1.0514

1280 / 1.0514 = 1217 turns

1217 × o.00133 = 1.62'  tube high perfect wind

1.62' × 1.12 = 1.82' actual tube winding height


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wiccakingkamui

6 years ago

2' tall, 3.5" diameter, 26 awg wire that is 1280' long will I have enough?

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rickharris

6 years ago

Where is the question here?

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rickharrissteveastrouk

Answer 6 years ago

Whereas I can accept that English isn't all peoples first language google translate can do better than that.