106Views10Replies

Author Options:

Making new tesla? Answered

Will 1280' (feet) coil the, 26 awg wire

Discussions

The forums are retiring in 2021 and are now closed for new topics and comments.
0
iceng
iceng

Best Answer 7 years ago

Wat dia in feet ?

0
iceng
iceng

Answer 7 years ago

Then one coil of #26 awg wire diameter o.015940" is a o.00133' added to the tube  results in a true o.33466' diameter which multiplied by Pi uses 1.05137' of wire per turn.

A 1280' length of wire divided by 1.0514' will allow 1217 turns of wire and
multiplied by wire diameter will need tube at least as high as 1.62' or 19.5"..
This assumes a perfect winding.  In practice add 12% slop to 1.82' or  21.8" tube height.

A.

0
wiccakingkamui
wiccakingkamui

Answer 7 years ago

Did you say I'll only get half of it done with this spool

0
iceng
iceng

Answer 7 years ago

1/3' dia =o.33333333333333' + o.00133 = o.33466' dia × 3.14159 = 1.0514

1280 / 1.0514 = 1217 turns

1217 × o.00133 = 1.62'  tube high perfect wind

1.62' × 1.12 = 1.82' actual tube winding height


0
wiccakingkamui
wiccakingkamui

7 years ago

2' tall, 3.5" diameter, 26 awg wire that is 1280' long will I have enough?

0
rickharris
rickharris

7 years ago

Where is the question here?

0
steveastrouk
steveastrouk

Answer 7 years ago

You just asked it......

0
rickharris
rickharris

Answer 7 years ago

Whereas I can accept that English isn't all peoples first language google translate can do better than that.