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what would happen if you put a rope around the world and tied one end to the front of a house and one to the back of the house the held on to it and cut it on the other side (not the on your holding on to)

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Hi, What i mean by the question is how long would it take to fall EG: 1 second, 1 minute

. The same amount of time it would take a ball to fall from the same height. For that problem, the rope, house, and World (other than producing gravity) don't have anything to do with it

When the moon is in the 7th house, and Jupiter aligns with Mars then peace will guide the planets, and love with steer that stars.......

. Geez. You ARE old. heehee

Don't get me started.....I will start reciting lyrics from the TROGGS next LOL

The rope would flop to the ground. Wouldn't it?

Searches for trick question, can't find one.

Yeah, it would fall to the ground.

No, you'd actually go flying round the world.

Why? He didn't say there was any tension on it, he didn't say it was off the ground in any way - it's just a rope on the ground, except for the last couple of feet. The length of rope in between is irrelevant.

but look, say if you scaled it down, to a cricket ball, what would happen?

:-)

It would get stuck in the seams? I think Slayer7 may have mis-typed the question - there must be something missing from it.

well would a football or golf ball do?

. The small objects you are talking about don't have much of a gravitational field to attract the rope.

Oh, I was working with an outside gravity ;-) (and the house at the north pole)

. Your position on the globe will have no practical effect on the problem.

Are you scaling up the other factors--friction, tension on the rope?

Let's wrap a rope around a 100 foot circumference sphere that has some surface texture. Say it takes about 100 lbs of force to get a little tug at the end of the rope--due to friction and the rope stretch.

Scale that up to earth size--the circumference of the earth
at the equator (in feet) is 24,902 * 5,280 = 131482560

Divide by 100 (our rope length), then multiply by 100 lbs/force per rope length (don't bother with the math as the result is the same.) Results: you'd need to apply a pulling force of 131,482,560 lbs to feel it on the other end....

(It's not a realistic scenario, but unless you could control what the rope contacts, IMO you'd average way more friction than 100 lbs/100 ft could overcome...Of course, the rope would break long before the applied force was evenly spread out.)

That's not even considering elongation of the rope, too...

Nothing if their wasn't ALOT of tension.