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custom cellphone battery charger drains out the cellphone battery..why??
I made a cellphone battery charger from 3 AA batteries.The combination of 3 AA batteries was at a higher potential than the cellphone battery, but when i connected both of them for charging, the potential of 3 AA batteries remained same but the cellphone battery was completely drained.why??If someone could explain maybe??
Comments
Best Answer 7 years ago
These are some of your possible problems when there is a utter lack of
information beyond the main complaint and we have to use the
Jedi remote viewing to see your schematic:¬o
7 years ago
schematic
Answer 7 years ago
A low forward diode prevents reverse discharge.
Answer 7 years ago
a 1N4007 will do, i suppose
I already have it at home
Answer 7 years ago
While a 1N4007 will do as well as a 1N4001.
A 16¢ 3A 40V schottky diode with a lower forward drop can charge a little bit more.
Thanks for selecting my answer.
A
Answer 7 years ago
i got it now ...thanks
7 years ago
the batteries were connected in series
+ve of 3 AA batteries was connected to +ve of cellphone battery and -ve of 3 AA battery was connected to -ve of cellphone battery
Answer 7 years ago
What is the voltage when you have them hooked up together Without the electronic one way valve special diode I texted about ??
Answer 7 years ago
4.44 V
Answer 7 years ago
wid the multimeter
i dint get the spl diode way
7 years ago
wires are not connected to wrong pins certainly
and i dont think they are no load voltage cz they lit a number of leds
here are the circuit and led lighting
7 years ago
Picks help
7 years ago
potential of 3 AA batteries(4.44V) was higher than cellphone battery(was lesser than 2.5V)
7 years ago
Did you connect the batteries in series (for a total of 4.5 V), or in parallel (for more current, but only 1.5 V)? The charger must have a higher voltage (usually significantly higher) than the battery being charged.
7 years ago
Can you show your schematic?