0kiffer360seandogue Answer 11 years ago right, its the formula. i never can rember the correct formula. (c+3)(c2-3c+9) i think.

0seandoguekiffer360 Answer 11 years ago Ding!... I guess I'd forgotten that there's a formula for disemboweling a cubic equation. I played the "guess the first term" game...

0NobodyInParticular 11 years ago I suspect that you were supposed to memorize the factorizations of the sum of cubes, difference of cubes, difference of squares, and perfect square trinomials. If you memorize these, you will save yourself a great deal of trouble. (a^3^ + b^3^) = (a^3^ - b^3^) = (a^2^ - b^2^) = (a^2^ + 2ab + b^2^) = (a^2^ - 2ab + b^2^) =

0seandogue 11 years ago Perhaps start by thinking of it as a disguised quadratic instead of a cubic equation?

## Comments

11 years ago

With Mathematica.

Answer 9 years ago

(3 + c) (9 - 3 c + c^2)

11 years ago

c^3+27

addition of cubes

(c+3)(c^2+3c+9)

Am I reading the problem wrong?

Answer 11 years ago

No, but your answer is wrong. close, but wrong.

Answer 11 years ago

right, its the formula. i never can rember the correct formula. (c+3)(c2-3c+9) i think.

Answer 11 years ago

Ding!... I guess I'd forgotten that there's a formula for disemboweling a cubic equation. I played the "guess the first term" game...

11 years ago

I suspect that you were supposed to memorize the factorizations of the sum of cubes, difference of cubes, difference of squares, and perfect square trinomials. If you memorize these, you will save yourself a great deal of trouble.

(a^3^ + b^3^) =

(a^3^ - b^3^) =

(a^2^ - b^2^) =

(a^2^ + 2ab + b^2^) =

(a^2^ - 2ab + b^2^) =

11 years ago

Another clue is C cubed = -27

11 years ago

Perhaps start by thinking of it as a disguised quadratic instead of a cubic equation?