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how much power do i need to heat 20 awg nichrome wire? Answered

im using 2 9 volts and its not working

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KellyCraig
KellyCraig

1 year ago

It might help if you gave a bit more background. Several on this site might be able to offer information, in addition to formulas or laws, you hadn't thought of.

It sounds like you are trying to make some sort of igniter. If so, you don't need the power supply to run very long. Just long enough to fire a rocket, commit arson, etc.

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VikasM51
VikasM51

2 years ago

Any answer about my post

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frollard
frollard

10 years ago

Seconded what a lot of others said -- a) use ohms law to calculate how much current you need to draw based on the resistance
b) 9 volt batteries suck. Build one of the hundreds of available power supplies here on ibles.

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G-force777
G-force777

Answer 10 years ago

thank you, any suggestions? i need a very small one, about the size of the 2 9vs or bigger

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frollard
frollard

Answer 10 years ago

Consider designing around a bigger battery pack? AA or C or D pack a WAY bigger punch than 9v (technically 6x AAAA), are cheaper (per watt-hour) and easier to find rechargables.

Do you absolutely have to run it on batteries?

Measure the resistance of the length of wire, figure out what voltage you will apply to it, then you know how much current will pull.

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G-force777
G-force777

Answer 10 years ago

thanks, i intend to use this for a fireworks ignitor, so id like it to be portable. it has enough power to make steel wool ignitors work, but they arnt reusable. and did you mean AAA? ive never seen AAAA

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frollard
frollard

Answer 10 years ago

AAAA is one size smaller than AAA...and AAA's suck too.

search 'kipkay 9 volt battery hack"

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G-force777
G-force777

Answer 10 years ago

alright i did, but if that is the same equivelent voltage of a 9v why bother?

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frollard
frollard

Answer 10 years ago

because imagine a battery is a pump. a pump that moves electrons (instead of some physical fluid).

The battery size plays a few roles-- generally electrochemical cells put out around 1.5 volts, hence why a 9 volt has 6 AAAA's in there, because volts are a measure of 'pressure' in simple terms, they are good at getting the voltage up when put together. Trouble with them is, they are so compact, there's not a lot of surface area (or volume in this case) for the battery to do its job, so it produces the voltage, but can't spit out enough current. Current is total volume of stuff going from A to B. Total power (watts, generally) is a measure of voltage times amps, so while you have the voltage you need, the smaller batteries can't put out the amperage, and thus can't put out the wattage required to heat the wire.

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G-force777
G-force777

Answer 10 years ago

so by doing this it basicly ups the amperage? that makes sense since it is the case with arc welders

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G-force777
G-force777

Answer 10 years ago

i have a 24 volt transformer, what batteries should i use for it

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frollard
frollard

Answer 10 years ago

transformers generally don't take in DC voltage, so batteries are no use to you.

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G-force777
G-force777

10 years ago

yeah i have them in a parralel circuit, and the feedwire is much bigger... 16 gauge, however the wires from the control to the detonation area are smaller... this may be half the problem, however when i attatched the nichrome directly to the leads where the detonation wire connect nothing happened. also possibly 6v batteries? like the heavy duty toy car ones?

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G-force777
G-force777

10 years ago

so if i use a chain of say 6 C batteries with 1 inch of 20 awg nichrome at about 24 gauge. i think that for the sake of portbility im going to possibly put a transformer where the 9vs where and have an external power source that would plug into the control box

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G-force777
G-force777

10 years ago

its about an inch of a wire about 24 gauge solid strand. im trying it qith 2 9v's but its not working, i think the batteries may just be low

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NachoMahma
NachoMahma

10 years ago

. Depends on how much wire you have.
. Find out the ohms/ft (or m or whatever unit is convenient) for your wire and multiply by how many feet (or m or whatever) you have.
. You know the volts and now you know the resistance - Ohm's Law will tell you the current. Then you can compute your power output (W).