verilog code ?
I have made sample code for 4 bit ALU and 3 to 8 decoder to make 4 bit processor . as designer we can design anything so I have started to design processor with two function ALU and decoder
4 bit alu
Module alu (a,b,s0,s1,s2 f);
Input a,b,s0,s1,s2;
Output f;
Reg [3:0];
Always @(s0,s1,s2);
Begian
Case (s0,s1,s2);
3b’000 :f=(a&b);
3b’001:f= (a|b);
3b’010 :f= ~(a&b);
3b’011 :f= ~ (a|b);
3b’100:f=(a^b);
3b’101: f=(a*b);
3b’110: f=(a+b);
3b’111:f=(a-b );
End case
End module
3to 8 decoder
Module decoder (a2,a1,a0, d7,d6,d5,d4,d3,d2,d1,d0);
Input a2,a1,a0;
Output d7,d6,d5,d4,d3,d2,d1,d0;
Wire [7:0];
Always @(a2,a1,a0);
Begin
Case (a2,a1,a0);
4’b000:( d7,d6,d5,d4,d3,d2,d1,d0)=00000001;
4’001: (d7,d6,d5,d4,d3,d2,d1,d0)=00000010;
4’b010: (d7,d6,d5,d4,d3,d2,d1,d0)=00000100;
4’b011: (d7,d6,d5,d4,d3,d2,d1,d0)=00001000;
4’b100:( d7,d6,d5,d4,d3,d2,d1,d0)=00010000;
4’b101:( d7,d6,d5,d4,d3,d2,d1,d0)=00100000;
4’b110: (d7,d6,d5,d4,d3,d2,d1,d0)=01000000;
4’b111: (d7,d6,d5,d4,d3,d2,d1,d0)=10000000;
Endcase
Endmodule
I don't understand how to connect 4 bit Alu with
3 to 8 bit decoder to make 4 bit processor
4 bit alu
Module alu (a,b,s0,s1,s2 f);
Input a,b,s0,s1,s2;
Output f;
Reg [3:0];
Always @(s0,s1,s2);
Begian
Case (s0,s1,s2);
3b’000 :f=(a&b);
3b’001:f= (a|b);
3b’010 :f= ~(a&b);
3b’011 :f= ~ (a|b);
3b’100:f=(a^b);
3b’101: f=(a*b);
3b’110: f=(a+b);
3b’111:f=(a-b );
End case
End module
3to 8 decoder
Module decoder (a2,a1,a0, d7,d6,d5,d4,d3,d2,d1,d0);
Input a2,a1,a0;
Output d7,d6,d5,d4,d3,d2,d1,d0;
Wire [7:0];
Always @(a2,a1,a0);
Begin
Case (a2,a1,a0);
4’b000:( d7,d6,d5,d4,d3,d2,d1,d0)=00000001;
4’001: (d7,d6,d5,d4,d3,d2,d1,d0)=00000010;
4’b010: (d7,d6,d5,d4,d3,d2,d1,d0)=00000100;
4’b011: (d7,d6,d5,d4,d3,d2,d1,d0)=00001000;
4’b100:( d7,d6,d5,d4,d3,d2,d1,d0)=00010000;
4’b101:( d7,d6,d5,d4,d3,d2,d1,d0)=00100000;
4’b110: (d7,d6,d5,d4,d3,d2,d1,d0)=01000000;
4’b111: (d7,d6,d5,d4,d3,d2,d1,d0)=10000000;
Endcase
Endmodule
I don't understand how to connect 4 bit Alu with
3 to 8 bit decoder to make 4 bit processor
Discussions
4 years ago
I have made table for decoder and ALU
4 bit ALU
S2 S1 S0 F
0 0 0 F= A and B
0 0 1 F= A or B
0 1 0 F= A Nand B
0 1 1 F= A nor B
1 0 0 F= A Xor B
1 0 1 F= A X nor B
1 1 0 F= A addition B
1 1 1 F= A subtraction B
S2 S1 S0 A B F
0 0 0 0 0 0 AND logic
0 1 0
1 0 0
1 1 1
0 0 1 0 0 0 Or logic
0 1 1
1 0 1
1 1 1
0 1 0 0 0 1 NAND
0 1 1
1 0 1
1 1 0
0 1 1 0 0 1 NOR
0 1 0
1 0 0
1 1 0
1 0 0 0 0 0 Xor
0 1 1
1 0 1
1 1 0
1 0 1 0 0 1 Xnor
0 1 0
1 0 0
1 1 1
1 1 0 0 0 0 addition
0 1 1
1 0 1
1 1 0
1 1 1 0 0 0 subtraction
0 1 1
1 0 1
1 1 0
Answer 4 years ago
Appears as the table includes improbable 6 bit wide data on a 4 bit ALU.
If the processor hardware design is to include a combination of instruction and data wider then the ALU surely make it a multiple of 4 bits.
Answer 4 years ago
data register is 4 bit
instruction register is 4 bit
Answer 4 years ago
So including NOP you have 15 other instructions.
AND,OR,ADD,SUB,ROTATE,NOT,NAND,NOR,XOR,JUMP,SKIP=,SKIP>,SKIP>,SKIP<>,SKIPonCARRY,SET,CLEAR
Answer 4 years ago
thats ok but how to write verilog code I mean I can write code for ALU , decoder , counter but how to write for processor
I have to write like this
module processor (input output )
input ;
output.;
always @(posedge);
endmodule
or I have to write like this
module processor (input output )
input ;
output.;
always @(posedge);
module ALU (input output )
input ;
output.;
always @(posedge);
endmodule
module decoder (input output )
input ;
output.;
always @(posedge);
endmodule
module counter (input output )
input ;
output.;
always @(posedge);
endmodule
module register (input output )
input ;
output.;
always @(posedge);
endmodule
endmodule
4 years ago
Connect physically or via as yet unsubscribed instructions ?
You seem to be describing bitwise ALU operations
You need to incorporate a 4 bit lookup table and implied address jumping using a flag to output 8 bit info on a 4 bit ALU as two sequential 4 bit words.
Answer 4 years ago
data register is 4 bit wide
and instruction register is 4 bit wide
4 years ago
Will really help you - The book as well
Answer 4 years ago
+1