Bit Banging Step-by-step: Arduino Control of WS2811, WS2812, and WS2812B RGB LEDs




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Disclaimer: over the past year, a few different libraries have been written for controlling these ubiquitous RGB LEDs by fellow makers from Adafruit, PJRC, and the FastSPI project.  The libraries work great, and we should try them all out.  Recently, we were asked by a few people how the low-level code really worked.  With the hope that others find the explanation useful, we put together this Instructable with a detailed answer.

When we want a microcontroller to send/receive data to/from devices using some form of digital logic, we often do so by way of standard protocols such as SPI, I2C/TWI, UART, etc.  However, there comes a time in every embedded hardware programmer's life where it is convenient or necessary to roll-up her sleeves, and crank-out her own protocol.  Such is the case for controlling the ubiquitous RGB LEDs from WorldSemi: the WS281X series.

It should be noted that there have been successful attempts to use the SPI protocol for controlling these LEDs.  Nevertheless, given the nature of their communication protocol (described below) this is a perfect setting for implementing a custom solution using a programming technique known as bitbanging.  This technique allows us to mimic different functions of specialized hardware using software.  In this case, we'll use it to toggle a digital output pin on the ATMega328p microcontroller in a highly precise manner, so that the digital signal created allows us to turn on and off a 1-by-60 array of WS2812 RGB LEDs.

Difficulty level: Beginner+ (some familiarity with Arduino programming)
Time to completion: 15-30 Minutes

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Step 1: List of Materials

Inside the WS2812 and WS2812B packages resides an embedded version of the WS2811 constant-current LED driver, as well as 3 individually controlled LEDs; one red, one green, and one blue. In a compact package, the WS2811 includes:
- An internal oscillator
- A signal reshaping and amplification circuit
- A data latch
- A 3-channel, programmable constant current output drive
- 2 digital ports (serial output/input)

Despite all the intricacies under the hood, we only need to worry about one thing—besides providing power, of course—which is to send ones (1s) and zeros (0s) over to the serial input port according to what we'd like for the LEDs to do. And so, we first need to be clear as to what we want the LEDs to do before moving on to the how we want to do it.


This Instructable focuses on the firmware to communicate with the WS281X, so all we really need to follow along is a computer running the latest version of the Arduino programming interface (avaliable for OS X, GNU/Linux, and Widnows):
Arduino IDE V1.0.5

If we want to see the code controlling an actual WS2812 RGB LED, then we need the following parts:
1 x WS2812 RGB LED (pre-soldered onto a tiny breakout board)
1 x Solderless Breadboard
Solid Core Wire (assorted colors; 28 AWG)
1 x Arduino Uno R3
1 x Breakaway Pin Connector, 0.1" Pitch, 8-Pin Male

Step 2: Principles of Operation

From a high-level, we want to control the intensity and color of the WS2812.  Whereas intensity is an intuitive concept (fully on, fully off, and some range of intermediate values), color deserves a short explanation for those unfamiliar with RGB LEDs.  As mentioned a few lines ago, the WS2812 contains 3 tiny LEDs that are very close to one another.  When we turn them on simultaneously, our eyes perceive a combination of red, green, and blue light, which we interpret as different colors—this is also the principle behind the pixels on our computer screens.  By changing the intensity of each LED relative to the other two, we can get a wide range of colors; for example, if we set the red, green, and blue LEDs to their maximum intensity our eyes perceive a whitish color.

We have a good high-level view of what we'd like the LEDs to do, but we need to translate it into something that the WS2812 can understand.  It turns out that this is not difficult to do, and is similar to how colors work on most digital displays (e.g., the screen on which you're reading this!).  The intensity of all 3l LEDs inside the WS2812 can be independently set to a value ranging from 0 (fully off) to 255 (fully on). So to set the color to whitish as mentioned above, we need to tell the embedded WS2811 driver chip: 

“Hey! Set the red LED to an intensity of 255, the blue to an intensity of 255, and the green to an intensity of 255.” (as illustrated by the video demo below)

But how exactly are we going send this message to the WS2811?  We need to delve a little bit into digital logic (pun intended) to know exactly how to communicate these and any other allowable intensity values.  After a couple of steps, we'll be able break down these values into their constituent 1s and 0s, and send them serially to the digital input port of the WS2811.

Step 3: From Decimal to Binary: Breaking Down Numbers Into 1s and 0s

Breaking a number down into 1s and 0s really means using its binary representation.  We need to remember that in a binary representation (e.g., 1101 in binary represents the number 13 in decimal), each position has a 'weight' that increases from right to left by a power of 2.  Starting with the first position on the right, the 'weights' are: 2^0, 2^1, 2^2, 2^3...  This is analogous to the decimal system where starting with the first digit on the right, the 'weights' increase by a power of 10: 10^0, 10^1, 10^2, 10^3...  Different than the decimal system where we can have any number from 0...9 at each position, in the binary system we can either have a 1 or a 0. 

Say we want to find the binary representation of the decimal number 23.  We first notice that 23 is a combination of the number 3 set in the 10^0 position, and the number 2 set in the 10^1 position, which means that when we weigh each number according to its position (2*10^1+3*10^0) we get the number 23.  If we tried to do the same in binary we would come up with the number 10111 because 1*2^4+0*2^3+1*2^2+1*2^1+1*2^0 = 23.  Of course, finding the binary representation of a relatively small number such as 23 can be done without much calculation.  But for larger numbers it becomes necessary to use the following algorithm:

- Increasing from 2^0, find the first power of 2 that's larger than the decimal number we have
- Starting with the power of 2 immediately below the one we found in the first step, divide the decimal number by the powers of 2 in decreasing order, all the way down to 2^0
- After each division step, we should get either a 1 or a 0 as the quotient, and some remainder value.  The remainder eventually should go to 0 (this can occur prior to the last division step)
- The 1s and 0s obtained as the quotients give the binary representation of the decimal number

Well, if we haven't gone through the process before, it all sounds like gibberish.  Nothing like going through an example to clear things up.  Say we want to find the binary representation of the decimal number 117.  Let's try to follow the algorithm above (I'll use some personal tweaks):

- We start with 2^0 which is smaller than 117, so we keep increasing.  2^1 is also smaller, keep going...  Okay so we get to 2^5 which is still smaller than 117, but as soon as we hit 2^6 we notice that it is the “first power of 2 that's larger than the decimal number we have”
- So we know we need to start with the power of 2 immediately below 2^6, which is 2^5.  [Personal tweaks] since we know that we're going to be dividing by all powers of 2 below 2^5, I write them all down beforehand so I don't forget.  I also remind myself that the remainder of the division should end in 0 (although it could turn into 0 along the way.
Divider       | Remainder  | Quotient
2^6 (64)     |                    |
2^5 (32)     |                    |
2^4 (16)     |                    |
2^3 (8)       |                    |
2^2 (4)       |                    |
2^1 (2)       |                    |
2^0 (1)       |                    |
-With everything set, we start the division steps:
Divider       | Remainder  | Quotient
2^6 (64)     | 117             | 1
2^5 (32)     |  53              |
2^4 (16)     |                    |
2^3 (8)       |                    |
2^2 (4)       |                    |
2^1 (2)       |                    |
2^0 (1)       |                    |
117 divided by 64 gives a quotient of 1 and a remainder of 53.  Thus we know that in the 7th position of our binary representation of 117, there'll be a 1 (i.e., 1XXXXXX).  To get the other positions we simply continue the division process:
Divider       | Remainder  | Quotient
2^6 (64)     | 117             | 1
2^5 (32)     | 53               | 1
2^4 (16)     | 21               | 1
2^3 (8)       | 5                 | 0
2^2 (4)       | 5                 | 1
2^1 (2)       | 1                 | 0
2^0 (1)       | 1                 | 1
- And so, we get that the binary representation of the decimal number 117 is 1110101.  We need to remember, that even if the remainder goes to 0 before the last division step, we need to continue the process all the way down to 2^0.  Thus, in the case of the decimal number 48:
Divider       | Remainder  | Quotient
2^5 (32)     | 48               | 1
2^4 (16)     | 16               | 1
2^3 (8)       | 0                 | 0
2^2 (4)       | 0                 | 0
2^1 (2)       | 0                 | 0
2^0 (1)       | 0                 | 0
The binary representation is 110000 as opposed to 110, which we would get if we stopped diving when the remainder first reached 0.  Knowing how to break down a number into its constituent 1s and 0s is very much necessary for being able to transmit data to the WS281X.

Step 4: From Binary Numbers to Digital Logic

Okay, so now that we're familiar with the binary representation of decimal numbers we can communicate the intensity values we want to the WS2811 LED driver IC.  Since the values go from 0 to 255 for each LED, we will need 8 positions (called bits in digital logic) to cover the entire range—255 is 11111111 in binary.  And, we'll need 24 bits to transmit the values for all 3 LEDs inside each WS2812.  But how exactly can we tell the WS2811 that we want a 0 or a 1.  Well, it turns out that we need to manipulate the timing of a square wave signal to do this.

DisclaimerThere is a small variation of the timing described below depending whether you're using an actual WS2811 IC, or the embedded version inside the WS2812/WS2812B.  The numbers used below correspond to the latter case (WS2812/WS2812B).  If you're using the WS2811 IC then consult the datasheet for the slightly different numbers (other than that, everything else described below is the same).

Principle of operation
The WS2811 expects two things:
1)  A pulse (i.e., rectangular) wave signal with a frequency around 800KHz—other frequencies work as well, but we'll stick to 800KHz in this tutorial—that sets the intensity values in an internal shift register.  Let's note however, that the WS2811 behaves differently than a standard shift register in that the data are shifted in a First-In Last-Out fashion. 
2)  After the data are shifted into place, the WS2811 expects a low signal lasting at least 50μs in order to latch the data to their respective outputs.

Shifting the data
Those unfamiliar with the term 'pulse wave' might have heard of its special case: the square wave.  These type of non-sinusoidal signals consist of an alternating amplitude between a fixed maximum and a fixed minimum at a constant frequency.  When the alternation occurs symmetrically, that is, when the time during which the signal has a maximum value is identical to the time during which the signal has a minimum value, then we have the special case of a square wave.  At around 800KHz, each period of the pulse wave is around 1.25μs long (1/1.25μs = 800KHz).  For communicating with the WS2811 we need to adjust the time during which the signal is either high or low in order to signal a 0 or a 1.  There's a mistake in the datasheet from WorldSemi, so the real values should be (credit to the folks over at Adafruit for catching this):

Transmitting a 1:
Time for the signal to remain high (T1H): 0.8μs
Time for the signal to remain low (T1L): 0.45μs

Transmitting a 0:
Time for the signal to remain high (T0H): 0.4μs
Time for the signal to remain low (T0L): 0.85μs

Latching the data
After sending all the bits corresponding to the intensity values of all the LEDs that we want to control, then we need simply hold the value of the pulse wave at its minimum value for at least 50μs.

Transmitting a 'latch command':
Time for the signal to remain low (TL): >=50μs

This type of signal has the special properties of being self-clocked, and non-zero return (NZR).  So, what remains is to see how we can set our ATMega328p to produce a precisely timed signal so that we can transmitting to the array of WS2812 RGB LEDs.  [Spoiler alert!]  We'll be using the bitbanging technique.

Step 5: Bitbanging a Pulse Wave on an ATMega328p Microcontroller

One of the advantages of using a microcontroller as opposed to, say a computer's CPU, is that we have a very tight control over the timing of the instructions we program into it.  In fact, to show how precise that control can be, we'll be using assembly instructions instead of the typical high-level functions such as digitalWrite.  The use of assembly allows us to know exactly how many clock cycles are taken up during the execution of each instruction.

Since the Arduino Uno R3 development board maintains a 16MHz external clock signal on the onboard ATMega328p, the microcontroller executes a 1 clock-cycle instruction in exactly 62.5ns (1/16MHz = 62.5ns).  Since we can find out how many clock cycles each instruction takes, we can precisely control how many instructions we need to generate our signal.

As we saw previously, in order to transmit a 1 to the WS281X chip we need to transmit a signal that stays at a maximum (HIGH) value for 0.8μs, and then stays at a minimum (LOW) value for 0.45μs.  Thus, we want to write a list of instructions that:

- Set digital pin to HIGH
- Wait 0.8μs
- Sets digital pin to LOW
- Waits 0.45μs

In assembly language, this can be achieved by the following code:

  asm volatile(
    // Instruction        Clock   Description   Phase     Bit Transmitted
    "sbi  %0, %1\n\t"  // 2      PIN HIGH       (T =  2) 
    "rjmp .+0\n\t"        // 2      nop nop         (T =  4)
    "rjmp .+0\n\t"        // 2      nop nop         (T =  6)
    "rjmp .+0\n\t"        // 2      nop nop         (T =  8)
    "rjmp .+0\n\t"        // 2      nop nop         (T = 10)
    "rjmp .+0\n\t"        // 2      nop nop         (T = 12)
    "nop\n\t"               // 1      nop                (T = 13)
    "cbi   %0, %1\n\t" // 2      PIN LOW       (T = 15)
    "rjmp .+0\n\t"        // 2      nop nop         (T = 17)
    "rjmp .+0\n\t"        // 2      nop nop         (T = 19)
    "nop\n\t"               // 1      nop                (T = 20)      1
    // Input operands
    "I" (_SFR_IO_ADDR(PORT)), //%0
    "I" (PORT_PIN)            //%1

The first column includes the assembly instruction followed by a linefeed and tab characters, which make the final assembler listing generated by the compiler more readable.

The second column shows the number of clock cycles each instruction takes.  For this set of simple instructions there is only one possible value, we'll see later how some instructions (e.g., conditional) may have 1, 2, or 3 possible values.  Remember that each clock cycle on the 16MHz Arduino Uno takes 62.5ns.

The third column shows a very brief description of what each operation does.

Using the term a bit loosely, we use it to indicate the cumulative sum of clock cycles taken by the instructions that have been executed thus far.

In order to send a single 255 value—11111111 in binary—to the WS281X we need to repeat this set of instructions 8 times.  In addition, if we insert a 50μs (or greater) pause between transmissions of the 8-bit sequence, the WS281X latches the transmitted data to its output register.  Once the data are latched,  the first LED (green) of the WS281X should turn on to a maximum brightness level.  The Arduino sketch inside demonstrates this operation.

To send a 0 we need to change the code that produces a 1 by decreasing the time during which the signal has a HIGH (maximum) value, and increasing the time during which the signal is at a LOW (minimum).  In addition, we should note that the values to each LED should always be specified using 8 bits.  For instance, if we wanted to send a value of 105—1101001 in binary—we would need to send the 8 bits 01101001 including the leading 0.  The code that produces a 0 looks like:

  asm volatile(
    // Instruction        Clock   Description   Phase     Bit Transmitted
    "sbi  %0, %1\n\t"  // 2      PIN HIGH       (T =  2) 
    "rjmp .+0\n\t"        // 2      nop nop         (T =  4)
    "rjmp .+0\n\t"        // 2      nop nop         (T =  6)
    "cbi   %0, %1\n\t" // 2      PIN LOW       (T =  8)
    "rjmp .+0\n\t"        // 2      nop nop         (T = 10)
    "rjmp .+0\n\t"        // 2      nop nop         (T = 12)
    "rjmp .+0\n\t"        // 2      nop nop         (T = 14)
    "rjmp .+0\n\t"        // 2      nop nop         (T = 16)
    "rjmp .+0\n\t"        // 2      nop nop         (T = 18)
    "rjmp .+0\n\t"        // 2      nop nop         (T = 20)      0
    // Input operands
    "I" (_SFR_IO_ADDR(PORT)), //%0
    "I" (PORT_PIN)            //%1

We can use the Arduino sketch inside to generate the signal whose image can be seen on the oscilloscope screen captures that are attached to this step.

Now, for the WS281X to display the whitish color we want, we need to send not one but three 255 values—in which case our signal consists of 24 ones—before waiting the 50μs for the data to latch.  We could do this by copy-pasting the eleven assembly instructions above 23 times (you can give it a try modifying the bitbang_255.ino sketch).  But the code would be impractical for sending values to more than one WS281X chips.  A better solution would be to write a loop that would iterate through the 8-bit values until all three of them have been sent.

The sketch inside includes a clear description of the steps taken to achieve the desired outcome.  The main section, written in assembly following the logic described above, looks as follows:

  asm volatile(
   //  Instruction        Clock   Description                           Phase
   "nextbit:\n\t"              // -    label                                     (T =  0)
    "sbi  %0, %1\n\t"     // 2    signal HIGH                         (T =  2)
    "sbrc %4, 7\n\t"       // 1-2  if MSB set                           (T =  ?)         
     "mov  %6, %3\n\t"  // 0-1   tmp'll set signal high          (T =  4)
    "dec  %5\n\t"           // 1    decrease bitcount                (T =  5)
    "nop\n\t"                  // 1    nop (idle 1 clock cycle)        (T =  6)
    "st   %a2, %6\n\t"    // 2    set PORT to tmp                 (T =  8)
    "mov  %6, %7\n\t"   // 1    reset tmp to low (default)     (T =  9)
    "breq nextbyte\n\t"  // 1-2  if bitcount ==0 -> nextbyte  (T =  ?)               
    "rol  %4\n\t"             // 1    shift MSB leftwards              (T = 11)
    "rjmp .+0\n\t"           // 2    nop nop                                (T = 13)
    "cbi   %0, %1\n\t"    // 2    signal LOW                          (T = 15)
    "rjmp .+0\n\t"           // 2    nop nop                                (T = 17)
    "nop\n\t"                  // 1    nop                                        (T = 18)
    "rjmp nextbit\n\t"     // 2    bitcount !=0 -> nextbit           (T = 20)
   "nextbyte:\n\t"          // -    label                                       -
    "ldi  %5, 8\n\t"         // 1    reset bitcount                       (T = 11)
    "ld   %4, %a8+\n\t" // 2    val = *p++                             (T = 13)
    "cbi   %0, %1\n\t"   // 2    signal LOW                           (T = 15)
    "rjmp .+0\n\t"          // 2    nop nop                                 (T = 17)
    "nop\n\t"                 // 1    nop                                        (T = 18)
    "dec %9\n\t"           // 1    decrease bytecount             (T = 19)
    "brne nextbit\n\t"    // 2    if bytecount !=0 -> nextbit     (T = 20)

The best way to understand the operation of this section is to consider different case scenarios, and follow the assembly code line by line.  For instance, we know that in order to send a value of 255, we need to send 8-bits with a timing corresponding to a 1.  In other words, the Digital Pin connected to the WS281X should remain HIGH for 13 cycles (0.8125μs), and LOW for 7 (0.4375μs).  Does the code above achieve this?  Let's see what happens when we first start transmitting:

asm volatile(
   "nextbit:\n\t"             // This is only a label for directing the jumps below.
    "sbi  %0, %1\n\t"     // The signal is set to HIGH, instruction uses 2 cycles.
    "sbrc %4, 7\n\t"       // True. Sending 255 implies current MSB is 'set' (=1).
     "mov  %6, %3\n\t"  // This is executed. “tmp” is set to HIGH.
    "dec  %5\n\t"           // Bit is being transmitted, decrease bit counter.
    "nop\n\t"                  // Need to idle for getting to the 13 clock cycles.
    "st   %a2, %6\n\t"    // Write the “tmp” value to the PORT (pin still HIGH).
    "mov  %6, %7\n\t"   // Set “tmp” to low for the next pass through the loop.
    "breq nextbyte\n\t"  // False. Bit counter isn't 0, use 1 cycle and continue.
    "rol  %4\n\t"             // Shift the byte value MSB leftwards.
    "rjmp .+0\n\t"           // Idle for 2 clock cycles. Phase reached T = 13.
    "cbi   %0, %1\n\t"    // Set signal to LOW.
    "rjmp .+0\n\t"           // Idle for 2 clock cycles.
    "nop\n\t"                  // Idle for 1 clock cycle.
    "rjmp nextbit\n\t"     // Bit counter wasn't 0 so jump to next bit. T = 20.

So the instructions that actually get executed generate a signal on the data pin that is 13 cycles HIGH (0.8125μs) and 7 LOW (0.4375μs), thus sending a bit with a value of 1 to the WS281X.  If we continue to study what the code does when the rest of the bits are sent, and what it does when values other than 255 are used, we'll get a deeper understanding of this particular implementation of bitbanging. 

I personally hope that you find this tutorial useful for getting started with bitbanging your own communication protocols whenever it's necessary!



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32 Discussions


1 year ago

Thanks for everything in here, very nice.

but I find a difficulties, I want to use your bit banging code to control "skylite RGB floodlight" shipped from china..well I can detect the bit-bang code using my oscilloscope but the receiver on floodlight RGB driver is 10V. how do I send the bit-bang code in 10V?

I've tried DC step-up but the signal from arduino is lost T_T.

1 reply

Reply 1 year ago

That's easy. You can easily find a op-amp and boost the 3.3V IO voltage directly up to 10 V.


2 years ago

Very good, nice and clear :)

Counting instruction cycles and padding with NOPs, takes me back!

For the beginner, who ought not be confused.... I've NEVER heard of a 'pulse wave' (other than in sci-fi films); One may send 'a pulse' or 'several pulses', or 'a train of pulses'. We use square waves in digital electronics (although the edges may get degraded).

A 'pulse wave' does not imply square wave, and in this context is unhelpful and degrades the nomenclature (IMHO).

It says that acrobotic is a "bloke" in the profile, although references above imply a female hand. The later I hope, as this piece is a strong role model for young women considering a career in electronics..... how it should be done ;)


4 years ago on Introduction

I have adjusted and tested the code for 8mhz, I tried this on a ATTiny85 and it works a treat

asm volatile(
"startbit:\n\t" // label
"ldi %5, 8\n\t" // reset
"nextbit:\n\t" // label

"sbi %0, %1\n\t" // SET OUTPUT HIGH
"sbrc %4, 7\n\t"
// Skip if HiBit in value is clear
"rjmp bitset\n\t" //
jump if HiBit is set
"cbi %0, %1\n\t" // clear output bit

"dec %5\n\t" // decrement nBits
"rol %4\n\t" //
shift value left to get to next bit
"brne nextbit\n\t" // branch
if bits not finished
"rjmp nextbyte\n\t" // jump to next byte

"bitset:\n\t" // label
"rol %4\n\t" // shift value
left to get to next bit
"dec %5\n\t" // decrement nBits

"cbi %0, %1\n\t" // clear output bit
"brne nextbit\n\t" //
branch back if bits not finished
"nextbyte:\n\t" // label
"ld %4, %a8+\n\t" // val = *p++ a8

"cbi %0, %1\n\t" // clear output bit
"dec %9\n\t"
// decrease bytecount
"brne startbit\n\t" // if bytes not finished
start again
:: // Input operands Operand Id (w/
"I" (_SFR_IO_ADDR(PORT)), // %0
// %1
"e" (&PORT), // %a2
"r" (high),
// %3
"r" (val), // %4
"r" (nbits),
// %5
"r" (tmp), // %6
"r" (low),
// %7
"e" (p), // %a8
"w" (nbytes)
// %9

4 replies

Reply 2 years ago

is that all the code that you need if not could i please have it because im having trouble


Reply 4 years ago on Introduction

although I am very confused at what this bit of your code does...

if((rgb_arr = (uint8_t *)malloc(NUM_BYTES)))
//memset(rgb_arr, 0, NUM_BYTES);

can you explain ? I would like to make a really mini version of this for an ATTINY13 (1k/60bytes) and the malloc command uses quite a bit of flash to implement. Thanks


Reply 4 years ago on Introduction

Memory allocation is not always necessary, but you need to be careful with accessing the array. Here's a good explanation on Stack Overflow


3 years ago

Awesome! You are the man! I've been trying to write a bit-banger driver for these LED's (my son wants RGB LED strips in the front of his PC that cycle all kinds of different patterns and colors) and I was having a terrible time trying to get accurate delays. I built a little ATTiny85 board with a 24 mHz. (!) crystal and still could not get accurate, short pulses.

My mistake was trying to do it in C rather than ASM. Thanks so much... you've made a little slice of my life easier!


3 years ago

It is not a FILO (First-In-Last-Out) it is a FIFO (First-In-First-Out) shifting protocol.


3 years ago

Hello there.
Did you tested RGB-W LED named SK6812?
I'm just curious since I want to run this Red-Green-Blue-White color LEDs on single line in series with WS2812B.

Those LEDs are supported by Adafruit Neopixel library but coding is different so I have to choose whether line will be feeded by WS2812B signal OR SK6812 signal.

I think that ATtiny85 with piece of smart code can do the trick and act as converter between those two standards, so I can start with WS2812B strip, then convert its output from last pixel by ATtiny and continue the line with SK6812.

This can be done also opposite way if needed.

I know that I can simply run those strips separately using parallel wiring, but in my case it requires car interior dismantle, so that's the reason why I'm thinking about WS2812B>>>SK6812 signal converter.

Hey, another point to think about:
If I want to leave strictly serial conducting of WS2812Bs since it is very inconvenient to direct data wire to some "leaf" and then wire it back.
Its much better to use tree topology for leafs, so there is no need for return of signal wire.
BUT: If you make leaf of 3pixels, connecting them in parallel to main LED strip, you have to sacrifice next 3pixels on the main strip and mute them by black foil to simulate illusion that leaf AND main strip are addressable individually..
This is cheap and easy while making 3pixels leafs. But become expansive and also power consuming while there is need for 30pixel leafs.

In this case it should be very handy to power tree topology by ATTiny in each node, which will "eat" the data mentioned for the leaf LEDs and forward rest of signal to next LED in the main chain.

2 replies

Reply 3 years ago

Haha Lukas, I didn't realize you were looking for this solution everywhere. This is a nicely written explanation of the protocol.

This was solved with the FAB_LED library. The solution allows you to attach in the same strip LEDs using different protocols, like sk6812, ws2812 and apa106, where some are rgb, grb, grbw etc. Once done you manipulate only one array of pixels expressed in one format, then have the draw routine handle the conversions on the fly for each pixel.


Reply 3 years ago

Hello.Yes, my first question was broadcasted since I was not sure whether anyone respond to my silly question :-)

I ran into this same problem!

The issue seems to be this line:

"dec %9\n\t" // 1 decrease bytecount (T = 19)

which is doing an 8-bit decrement of the byte count which is stored across two 8-bit registers (the "w" constraint). Once you get to 86+ lights, you need the hi-byte and dec no longer works.

Fixed by doing this instead:

"sbiw %9,1\n\t" // 1 decrease bytecount (T = 19)


Reply 3 years ago

Thanks for the tip. Also, remember to combine it with the "nop" line above as the "sbiw" instruction takes two clock cycles instead of one like "dec" does.


3 years ago

Can it be done and how hard is it?
To connect 6 of those 4x4 ws2812 boards, 3 in series and to set up the arduino nano/mega to listen for 12-16v power incoming so it will start to flash the left side of the boards or the right side?
I wanna set up car turn light (orange color) that travel from one side to the other ( think larson scanner) but since the turn signal comes in short interval the arduino needs to be on all te time and when there is 12-16v power coming from the car left or right to flash the leds accordingly, maybe even throw some flashing lights in the code when not turning keep on red light at half brightnes or maybe some kind of animation.

How many LEDs can be controlled with Arduino UNO and using his beautiful library ??

I can theoretically handle thousands, since I am not subject to 2KB of RAM Arduino UNO. Right ??

1 reply

Hi, Hely. In theory you can handle thousands indeed! The main limitations are supplying enough power to them (each one can take up to 60mA but will happily run with less), and not running out of RAM.

One thing to keep in mind is that you may start seeing flickering once the # of LEDs is big enough. Setting each LED takes around 30us (which can't be changed), so if you need to set 1000, then your code will spend 30ms setting the colors. After the colors are set, then is when you display them.

Our eyes start noticing the flicker if the refresh rate is below ~20--30Hz, so you'll need to get creative with speeding up the way you set the colors (e.g., by connecting them in parallel to your Arduino, and performing port writes).



5 years ago on Introduction


What do you save in the char (p and rgb_arr) ?