# Charlieplexing the Arduino

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## Introduction: Charlieplexing the Arduino

This Instructable shows how to implement Charlieplexing, a technique that will allow you to control many more LEDs than you have pins. This shows how to configure 6 LEDs and use only 3 pins. You can extend this to many more LEDs. The exact number of LEDs that you can control with a given number of pins is given by n^2 - n where n is the number of pins used (i.e.,  3^2 - 3 = 9 - 3 = 6 LEDs using only n = 3 pins).

## Step 1: Charlieplexing the Arduino

Charlieplexing not only takes advantage of the two states that we normally change, HIGH and LOW, but also uses a third state by changing between OUTPUT and INPUT modes, which affects internal resistors on the Arduino.

For Charlieplexing 6 LEDs, we will setup six LEDs (L1 thru L6) and need to configure three pins (I chose Pins 13, 12, and 11) for each LED.

For each LED (L1, L2,....,L6), we need to set the pinMode (INPUT or OUTPUT) and the pin state (HIGH or LOW)

H: pinMode = OUTPUT; state HIGH
L: pinMode = OUTPUT; state LOW
Z: pinMode = INPUT; state LOW

For example, to configure LED L2, set pin 13 to H, pin 12 to L, and pin 11 to Z:

Pin13
pinMode(LED_1, OUTPUT);  //pinMode
digitalWrite(LED_1, HIGH);   // state

Pin12
pinMode(LED_2, OUTPUT);  // pinMode
digitalWrite(LED_2, LOW);   //state

Pin11
pinMode(LED_3, INPUT);  // pinMode
digitalWrite(LED_3, LOW);  // state

## Step 2: Configure Hardware

Connect two LEDs to each Pin; be sure to flip the LED so the Cathode (+) and Anode (-) are on the correct Pins. The cathode (+) has the longer leg and is shown in the schematic as the leg with the bend in it.

## 21 Discussions

I couldn't get L6 to work, looking at the sketch you have:

//turn on LED L6 pinMode
(LED_1, OUTPUT);
digitalWrite(LED_1, HIGH);
pinMode(LED_2, INPUT);
digitalWrite(LED_2, LOW);
pinMode(LED_3, OUTPUT);
digitalWrite(LED_3, HIGH);

I needed to change LED_3 to LOW:
digitalWrite(LED_3, LOW);

Then it worked.

Tim

The schematic is correct but the wiring is wrong. L5 and L6 are reversed. Also, seems to make more sense to run the wires from pins 13, 12, and 11 through the resistors first (just like the schematic) and dispense with the ground wires which don't make sense in this set up anyway. Finally, if it is wired correctly according to the schematic, then the code is incorrect. This is what the loop should be:
void loop()
{
//turn on LED L1
pinMode(LED_1, OUTPUT); //row 1
digitalWrite(LED_1, LOW);
pinMode(LED_2, OUTPUT); //row 2
digitalWrite(LED_2, HIGH);
pinMode(LED_3, INPUT); //row 3
digitalWrite(LED_3, LOW);

delay(1000);

//turn on LED L2
pinMode(LED_1, OUTPUT); //row 1
digitalWrite(LED_1, HIGH);
pinMode(LED_2, OUTPUT); //row 2
digitalWrite(LED_2, LOW);
pinMode(LED_3, INPUT); //row 3
digitalWrite(LED_3, LOW);

delay(1000);

//turn on LED L3
pinMode(LED_1, INPUT); //row 1
digitalWrite(LED_1, LOW);
pinMode(LED_2, OUTPUT); //row 2
digitalWrite(LED_2, LOW);
pinMode(LED_3, OUTPUT); //row 3
digitalWrite(LED_3, HIGH);

delay(1000);

//turn on LED L4
pinMode(LED_1, INPUT); //row 1
digitalWrite(LED_1, LOW);
pinMode(LED_2, OUTPUT); //row 2
digitalWrite(LED_2, HIGH);
pinMode(LED_3, OUTPUT); //row 3
digitalWrite(LED_3, LOW);

delay(1000);

//turn on LED L5
pinMode(LED_1, OUTPUT); //row 1
digitalWrite(LED_1, LOW);
pinMode(LED_2, INPUT); //row 2
digitalWrite(LED_2, LOW);
pinMode(LED_3, OUTPUT); //row3
digitalWrite(LED_3, HIGH);

delay(1000);

//turn on LED L6
pinMode(LED_1, OUTPUT);
digitalWrite(LED_1, HIGH);
pinMode(LED_2, INPUT);
digitalWrite(LED_2, LOW);
pinMode(LED_3, OUTPUT);
digitalWrite(LED_3, LOW);

delay(1000);
}