It is very important to save time, when you have to solve multiple questions in a minute.

That is why i make these algorithms to save time while giving exam.

I will show you, how can you make one.

If you have any questions, please comment below. I will reply ASAP.

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## Step 1: Make One Square and See What Is the Answer

__1 x 1 square__

**Answer :** obviously answer is **one**.

## Step 2: How Many Squares in 2 X 2 Square

__2 x 2 Square__

**Answer :** 4 small squares + 1 big square

= **5** squares

## Step 3: Same Thing for 3 X 3 Squares and 4 X 4 Squares

__3 x 3 ____Square__

**Answer :** 9 smallest squares + 4 medium size squares + 1 big square

= **14** squares

**4 x 4 ****Square**

**Answer :** 16 smallest squares + 9 medium size squares + 4 big square + 1 giant square

= **30** squares

## Step 4: Finally, How Can You Make an Equation

Search for clues in previous steps:

__3 x 3 Square__

Answer : 9 smallest squares + 4 medium size squares + 1 big square = 14 squares

__4 x 4 Square__

Answer : 16 smallest squares + 9 medium size squares + 4 big square + 1 giant square = 30 squares

Answer is 30 squares,

Which is 16 (smallest squares in 4 x 4) + 14 (Total squares in 3 x 3)

In 3 x 3 square and 4 x 4 square, there is one similarity,

9 squares + 4 squares + 1 square

Where , 9 squares = 3 multiplied by 3

4 squares = 2 multiplied by 2

1 square = 1 multiplied by 1

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**Calculation**

You only add smallest number of squares to previous calculation

list all the answers

1x1 Square : (1*1) = 1

2x2 Square : (1*1) + (2*2) = 1+4 = 5

3x3 Square : (1*1) + (2*2) + (3*3) = 1+4+9 = 14

4x4 Square : (1*1) + (2*2) + (3*3) + (4*4) = 1+4+9+16 = 30

5x5 Square : (1*1) + (2*2) + (3*3) + (4*4) + (5*5) = 1+4+9+16+25 = 55

So add up square of one through number of rows as shown above.

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This is how you make equations (see the attached image). If you have any questions, please comment below. I will reply ASAP.

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## 2 Discussions

3 months ago

Very Interesting Hacks by @hjajadiya

3 years ago

Very Interesting Instructable.