Today I am going to make a circuit for Short Circuit protection.This circuit we will make using 12V Relay.
How this circuit will Work - when short circuit will occur on the load side then the circuit will be automatically cut off.
Let's get started,
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Step 1: Take All Components As Shown Below
Step 2: Connect Button Switch to Relay
Firstly we have to solder Push button to the common pin and coil-1 pin of the Relay as solder in the picture.
Step 3: Connect Green LED
Next solder -ve leg of green LED to coil-1 pin and Normally Open (NO) pin of the Relay as you can see in the picture.
Step 4: Connect Red LED to Relay
Next connect -ve pin of Red LED to Normally close (NC) pin of the Relay and
Solder +ve leg of Red LED to +ve leg of green LED as solder in the picture.
Step 5: Connect 330 Ohm Resistor
Next we have to solder 330 ohm resistor between +ve legs of LEDs and coil-2 pin of the Relay as you can see in the picture.
Step 6: Connect Battery Clipper Wire to the Circuit
Solder +ve wire of battery clipper to coil-2 pin of Relay and
-ve wire of of battery clipper to common pin of the relay as solder in the picture.
Step 7: Connect Output Wire to the Circuit
Next connect +ve output wire to +ve of battery clipper/coil-2 of relay and
Solder -ve output wire to coil-1 pin of the Relay as picture.
Step 8: Connect Battery to Battery Clipper
Now our circuit is ready so connect battery to battery clipper.
How it's working - When we will connect battery then Red LED will glow. Now we have to press push button then Green LED will glow.
Step 9: Now Connect Load
Now we have to connect 9V LED as load to the output wires.As you can see in the picture 9V LED is glowing.
Step 10: When Short Circuit Occur
Unfortunately short circuit occur on the output wires then circuit will be automatically cut-off.
For again using this circuit press button switch then again 9V LED will glow.
Red LED - shows short circuit occur.
Green LED - Short circuit is not occur.
This type we can make short circuit protection circuit.
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