Plus-minus 5V Supply From 9V Battery (Part-2)

Hey guys! I am back.

Op-amps require a dual-polarity supply for proper operation. When working with battery supply, it becomes difficult to get a dual power supply for the op-amps. Presented here is a simple circuit that provides ±5V from a 9V battery.

Let's pick up from where i left last time.

Step 1: Fabricated Board

The image shows the fabricated PCB board, which I received from LionCircuits.

Let’s starts with the assembly of this board.

Step 2: Components Assembled Board

The above image shows all components assembled on the PCB Board. I have used a 9 v battery for input supply. When the supply is given to the board, voltage regulator IC1 converts 9V battery input into regulated 5V. This 5V output from IC1 is given to pin 8 of IC2. IC2 and capacitors C3 and C4 form the voltage inverter section that converts +5V to -5V. Converted -5V supply is available at pin 5 of IC2. Converted ±5V supply is thus available at connector CON2.

Step 3: Test Points

Test points -> Details

  • TP0 -> +9V
  • TP1 -> +5V
  • TP2 -> 0V(GND)
  • TP3 -> -5V

Step 4: Working and Output

Above 3 images shows receiving different voltages at the output 3 pin connector, Presented here is a simple circuit that provides ±5V from a 9V battery.

Enclose it in a water-proof box. Battery BATT.1 should be enclosed in the box. Fix CON 2 on the front or rear side of the cabinet, so that you can use the ±5V easily. Before using the circuit, verify the test points given in the table to ensure proper working of the circuit.

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    2 Discussions

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    throbscottle

    6 days ago

    Clever. Nice simple way to get split supplies. Do you find you get 10KHz noise on the output from the 7660?

    1 reply
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    DIYenthusiast1throbscottle

    Reply 5 days ago

    For the 5 v input supply, at the output side of IC 7660 getting 10K Hz of frequency, but that frequency can be decreased by adding external capacitor.