# SudoKube - Rubik's Sudoku Cube

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## Introduction: SudoKube - Rubik's Sudoku Cube

If you feel like your brain needs some exercise...

If you're looking for a smart challenge...

If you have an hour to build something cool...

i give you....

The SudoKube!!

A 3X3 Rubik's Cube, with Sudoku on each side.

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## Step 1: What You Need

here's a list of what you need:

1. Rubik's Cube (can be old, or cheap, or just one you can ruin without regrets)
2. Stickers that you can write on

## Step 2: Strip the Cube

Second step is to clean the cube. Meaning:

Peel the color-stickers off
Clean excess glue and sticker-traces that's left (with solvent or detergent - just don't use a lot)

You'll end up with a bare cube, black plastic only.

(if you love your cube - solve it for the last time before you undress it..)

## Step 3: Make Sudoku Stickers

1. Measure the size of one corner cube (mine was 2.1 cm X 2.1 cm)

2. Prepare 54 square Stickers (3X3X6=54)
maybe you can find ready stickers
I had to cut mine out from larger stickers

3. Make 6 sets of stickers with 1,2,3,4,5,6,7,8,9 on them (Sudoku is 1-9.. right?)
Don't forget to underline 6 and 9 to distinguish between them!

## Step 4: Stick 'em Up!!

Last thing you need to do is:

Stick a set of sudoku numbers stickers on each side of the stripped Rubik's Cube

(Make sure you stick them well - solving the SudoKube can become pretty violent!

And there you have it!! a home-made SudoKube!!

now...... just solve it!!!
good luck.....

http://nurne.blogspot.com

(does anybody want to make an instructable on solving it?.... heh)

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## 54 Discussions

with this in mind im down to 48 now...48 total combinations for one edge line. Now my head is frying. Struggling to simplify. Im posting this now lol as otherwise i may be posting the same one a long time from now and look like an arse lol. If someone can get past this point and explain it simply to show why my brain seems to be faulty please help me lol, as I dont even know the procedure aaaaaaargh. Reminds me of the original rubiks cube. Did anyone solve that by means of logic, does anyone, or do they find practical trial and error techniques get them past these points?

Oh, wait its less than 504, as 2,4,5,6 and 8 cant be on ends anyhow...224 maximum now. Its getting less...lol. I wonder if I can solve it this way faster than an expert can using the cube...that would be smart? Or stupid if Im rediculously slower...right so my prediction is ...Ill be faster lol oh challenge on... brb

9 numbers, 6 faces, original = 6 colours, 6 faces. hmmm... can't use original tactics, cant translate yet either. Experts would probably solve one line and check joined face until a match was made, then you would seem better to count all possible matches, which would be what? 1+2+3,1+2+4,1+2+5,1+2+6,1+2+7,1+2+8... just calculated 504 using excel... wow. Not a particularly mathematically memorable number.Then see how many have solved joined faces out of these 504? hmmm how do i do this without a cube...hang on Ill be back...

The thing is, there's no logical way to solve it, because there is no way to differentiate between the numbers that go with each 5 on each side; so it would take an extreme amount of luck, or an extreme amount of time.

THOSE THINGS ARE IMPOSSIBLE TO SOLVE None of my friends that can solve rubics cubes (even the 5x5x5 ones) could solve it

Curses, I wrote a nice long comment explaining why this doesn't work and the network went down so it didn't post. Long story short- you can't solve this like a "true" sudoku because... well, consider the 5 in your last step. It would have to be in, say, the top row on the left hand face, the bottom row on the right hand face and then there is no row available for it on the back face. The only way you can solve this is to ignore the opposite face (which is a bit of a cheat, opposite faces could then be identical and it becomes a lot easier to solve) or using a 4x4x4 cube which has enough rows and columns per face to avoid being overcontrained as this one is. I don't know whether the 4x4x4 case is possible, though, but I don't see any obvious reason why it shouldn't be.

It could be solved by simply assigning colours to the each set of 1-9 and then solved in exactly the same way as a normal cube.

Meaning you would end up with a same colour face for each of them? Or still a mix of colours but assigned 1-9?