Wireless Electricity Transmission Circuit




Introduction: Wireless Electricity Transmission Circuit

I love making and breaking electronics.

This is a simple circuit that can power a light bulb without any wires, at a distance of almost 1 inch! This circuit acts as both, step up Voltage converter and also wireless electricity transmitter and receiver. This is a really easy project to do, and could be used in many ways if improved. So lets get to it!

Step 1: Materials and Tools Necessary for the Project

So to make this circuit you will need:

1) NPN Transistor. I used 2N3904 but you could use any NPN transistor. Most commonly you could find BC 337, BC547 etc. (Any PNP transistor would work, just reverse the polarity of the connections.)

2) Magnet wire or insulated wire. About 3-4 feet of wire or less should be enough. (Magnet wires are just copper wires with very thin enamel insulation) You could find wires from most electronics, like transformers inside CFC Bulbs, inside speakers, inside motors, inside relays etc.

3)Resistor 1 Kilo Ohm. This resistor would be used to protect the transistor from burning out in case of overload or excess usage ad heat. You could use higher values upto 4-5 Kilo OHM. You could even decide not to use a resistor, but that would draw in more amps, thus draining your battery faster.

4) L.E.D light . I used a 2 mm Ultra Bright White L.E.D. You could use any L.E.D (Light Emitting Diode). For this circuit, the L.E.D only shows the circuit in action.

5) A 1.5 Volt AA Battery . ( Do not use batteries of higher voltage unless you want to damage your transistor.)

Tools needed:

1) Scissors or knife.

2) Soldering Iron (Optional). If you don't have a soldering iron, you could just twist the wires and leads for connection. That's what I used to do when I didn't have soldering iron. If you want to try the circuit on solderless breadboard, you are good to go.

3) Lighter (Optional). We will be using lighter to burn off the insulation from the wire, then just use a scissor or a knife to scrape off the insulation.

Step 2: Watch the Video to Learn How to Make It!!

Step 3: Recap of the Steps

So first of all you need to take the wires, and make a coil of 30 turns around a round object. Name this coil A. With the same round object, start coiling again. This time when you make your 15th turn with the wire, create a tap, and then coil another 15 turns. So now you have a coil with two ends and one tap. Name this coil B. Tie knots on the ends of the wires, so that it doesn't uncoil by itself. Burn the ends and the tap in order to take off the insulation from both the coils. If you don't want to use a lighter, use a scissor to scrape off the insulation from the ends of the wires and the tap. Make sure, the Diameter and number of turns on the coils are equal!!

Making the transmitter: Take the transistor, and place it so that the flat side is facing up and the leads are facing towards you. The lead on the left is the Emitter, the lead in the middle is Base, and the lead in right is the Collector. Take the resistor and connect one of its ends to the base of the transistor. Take the other end of the resistor and connect it one of the ends (not the tap) from Coil B. Take the other end from Coil B and connect it to the Collector of the transistor. If you want you could connect a small piece of wire to the Emitter of the transistor (It would work as an extension of the Emitter.)

Making the receiver: To make the receiver, just take Coil A and connect its ends to the leads from the L.E.D.

You are done making the circuit!!

Step 4: Circuit Schematic

Here is the schematic of the circuit. If you don't know anything about schematics, don't worry. In the next steps a diagram is provided.

Step 5: Circuit Diagram

So here is the diagram of the circuit.

Step 6: Using the Circuit

Just take the tap from coil B and connect it to the positive end of the battery. Connect the negative end of the battery to the Emitter of the transistor. Now if you bring coil A with the L.E.D close to Coil B, the L.E.D lights up!

Step 7: What Is the Science Behind This?

(I am just trying to explain the science behind this in simple words and analogies, and I know I am going to make mistakes. In order to provide the correct explanations I need to go into details, which I am unable to , so I am just gonna use common analogies for explaining the circuit ).

The transmitter circuit that we just created is an Oscillator circuit. You may or may not have heard about the Joule thief circuit which has striking resemblance to this circuit. A joule thief circuit, takes electricity from a 1.5 Volt battery, outputs electricity at a higher voltage but with thousands of intervals in between. A L.E.D requires 3 volts to light up, but a joule thief circuit could light up the L.E.D with 1.5 volt battery. So the Joule Thief circuit is known as a step up converter and also an oscillator. The circuit that we created is also an oscillator and step up converter. But the question might be, "How does it light up the L.E.D at a distance?" This happens due to induction. Lets use transformer for example. A normal transformer has a core with wires on either side. Lets suppose the wire on each side of the transformer is equal in amount. When electricity is passed through one coil, the coil becomes an electromagnet. If the electricity is oscillating voltage, that means the voltage would keep rising and dropping. So when an oscillating electricity is passed through the coil, the wire gains properties of electromagnet and then again loses electromagnetism when the voltage drops. A coil of wire becoming electromagnet and then losing its electromagnetic characteristics really fast is just like a magnet moving really fast in and out of the second coil. And when you pass a magnet really fast through coil of wires, you produce electricity, so the oscillating voltage in one coil on the transformer, induces electricity in the other coil of wire, and thus wirelessly electricity is transferred from one coil to the other. In our circuit, the air is the core, and there is oscillating voltage going through the first coil, so you induce A.C electricity in the second coil and light up the bulb!

Step 8: Uses and Tips for Improvements!

So for our circuit we just used a L.E.D to show the output. But we could do more than that! The receiver circuit receives A.C electricity, so we could use Large step up converter to use the output from the receiver coil to light up CFC bulbs! Also it is great for some cool magic tricks, fun gifts,and science projects for class. Also you could change the diameter of the coils and number of turns on the coils to maximize the results. Also you could try making pancake coils, and see how it goes! The possibilities are endless!!

Step 9: Troubleshooting

So this are the variations of problems you may face, and how to fix them:

1) Problem: The transistor becomes too hot!

Solution: Did you use a resistor of the right value? I didn't use a resistor the first time, and it started to smoke. If it does not solve the problem, then try using a heat shrink or using a transistor with higher amp rating.

2)Problem: The light does not light up!!

Solution: The problem is too broad. There could be many reasons behind the problem. But first check the connections. I accidentally swapped the Base and Collector connections, which caused a big problem for me. So check you connection first. If you have a multimeter check to see if you have continuity between your connections. Also make sure that the coils are of the same diameter. Also be careful there no shorting in the circuit.

I don't know about any more problems. But if you are facing some other problems, let me know! I will try to help as much as I can. Also I am a 9th grader, so my scientific knowledge is extremely limited, and so if I make any mistakes, help me find it out. Suggestions for improvements are more than welcome. Good Luck with your project!!!

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317 Discussions

Hey there little friend , i should have directly commented on your post but am replying for a reason , the circuit you gave is very correct up to your level (the circuit given by the burgersbite is just an cleaner representation of yours) and i gotta say you explained that stuff pretty well , in a bit more technical terms , the oscillator you've made acts like a feedback oscillator and when you put the receiver coil above it , what actually happens is mutual induction , or the rate of change of flux in the first coil results in the induced E.M.F in the other other coil.The higher the frequency of the oscillator the higher voltage you get , singe e=-d(flux) / dt , the smaller time it takes for one oscillation the higher emf you induce but sadly there is a factor which limits you to get 1000000 volts out of that battery , it is the more voltage to gain up , the more current you'll loose and at some point there will be negligible current through the second coil though the voltage is pretty high. So you cant put up good voltage with that battery. So my point was you're explanation of this circuit was mind blowing and super easy to understand. Keep up the good work kid.


Samad Haque

hey as magnetic flux through the coil is not changing (as we keep coils at constant distance) how can led keep glowing?

You can swap it with the one you had if you wish. All I did was edit it with Paint. The 15 came from the 1.5 volts lol.

From this schematic the current in both coils flow in the same direction, right?

However, take a look at the video when he turn the coil, it look like the current will flow in opposite direction.

if we put two wireless current in opposite side what will happen?

if we put two wireless current in opposite side what will happen?

if we put two wireless current in opposite side what will happen?

if we put two wireless current in opposite side what will happen?


I have a general question regarding NFC-WPT (wireless power transfer) system. Suppose, we have complete transmitting unit (transmitter coil and their electronics board) and receiving unit (receiver coil and their electronics board).

If we place transmitter and receiver coil close to each other, but the electronics board of transmitter place a bit far away from the transmitter coil by joining the copper wire.

Will this connection effect their power or not and how??

Thanks in advance,

It is a -DIODE-

Light Emitting Diode L.E.D

The 2N3904 is a 200 mA, 40 V, 625 mW transistor with a transition frequency of 300 MHz. https://goo.gl/6miUnB

He is running 1.2 Volts through it so I dont know how that changes its performance, if it changes the frequency. I dont know.

But if it is oscilating at 300MHZ then the diode is flashing at 150MHZ and we cannot see it blinking.

Direct current doesnt work on wireless because the fields that move the electrons are static.

The AC frequency waves push and pull the electrons through the circuit.


It is a -DIODE- Meaning lets current pass only one way.

Light Emitting Diode L.E.D

Since the power is AC it will activate on one cycle but not the other.

The 2N3904 Transistor is a 200 mA, 40 V, 625 mW transistor with a transition frequency of 300 MHz (https://goo.gl/6miUnB)

He is running 1.2 volts through it so I dont know how that effects the transistors performance. Does it change the frequency? I dont know.

So in effect if the transistor is running with those loads @ 300 mhz then the diode is on for 150Mhz where you wont see the blinking.

For these wireless circuits you need the alternating current to move the elctrons around. DC doesnt work wirelessly as the field is static and current does not move through circuit.

Its an oscillator, modelled on a Hartley circuit. Try an Ebers-Moll equivalent circuit, in a small signal simulation

How much is the output current of the above-mentioned circuit? What changes should i makes to get an output of around 200mA?

What is the mounting frequency ?