A Simple Current Amplifier

About: None of your buisness

a amplifier of current . when we touch the wires it glows but without the circuit it will not glow brightly.you can make it on a pref board or without it i am making it with a pref board.

Step 1: Things Required

things required-
1] 560 ohm resistor
2] NPN transisor
3] led
4]9v battery
5] battery snap

Step 2: The LED

you can use a diffused led if you want much of a glow . if you want a beam of light use a water clear type.

Step 3: The Circuit Digram

solder the circuit with the circuit digram.

Step 4: All Done!!!

you have made your current amplifier.
touch the both touch wires and the led glows brightly
without the circuit it will be very dim.

Step 5: Update

solder a 100k resistor between the base of the transistor and the touch pad

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    11 Discussions

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    Aabhishek Sharmavina1991

    Reply 2 years ago

    Absolutely no. He has made a touch sensor . The transistors amplify the current at that much extent that the small current signal passes through our body to complete the circuit..
    Thank you

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    MechackM

    3 years ago

    I want to amplify current from as low as 21ma to 750ma using a 5volt battery. Please assist me

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    samalert

    6 years ago on Introduction

    I tried making music sync LEd but the strip am using dont blink with great intensity they get max of 5v where they need 12v

    Now what i need is your circuitry to amplify the current.

    Can you please let me know if i can use yours to get max of 12v also what type of transistor or resistor to use to safeguard my LED strip and not burn my CAR

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    Rockser11

    7 years ago on Step 3

    thanks, im building an ipod base out of a coke can and this will be very helpful

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    simmer65

    7 years ago on Introduction

    Be prepared to burn up your transistor if you try this circuit. My NPN transistors have a max Base-Emitter voltage (Vbe) of 6 volts. This circuit will send way too much current through the base.

    If you want the LED to glow, remove the transistor and reduce the resistor. You will get about a 2v drop across the LED and 7v across the battery. To achieve a 50mA current (the brightness of an LED is determined by the current through it), use the equation V=IR or 7 = .05 * R......R=140 ohms.

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    zazenergy

    7 years ago on Introduction

    This is a good, simple experiment for an electronics enthusiast. Thanks for sharing!