zaerymoghaddam

As mentioned in the text, you can find it in my Arduino Editor.

Thanks Ashraf, Good luck :)

Hi OviBIf you're going to use the libraries you mentioned in your comment, then the code doesn't need to be changed that much. Methods I used are all defined in Adafruit library and they have provided these methods for both versions of the display (I2C as well as SPI) on top of GFX library. The only changes that I can imagine are:1 - Wiring (obviously)2 - Headers included on top of the code (SPI, GFX, 1306)3 - (Probably) some constant needed to be defined in the codeI suggest you to take a look at the following code and libraries that are included (and their order) on top of the code:https://github.com/jandelgado/arduino/blob/master/...You can see that it included both SPI and Wire library so my guess is that it should work in both cases. Wire is the underlying library that would be use...

Hi OviBIf you're going to use the libraries you mentioned in your comment, then the code doesn't need to be changed that much. Methods I used are all defined in Adafruit library and they have provided these methods for both versions of the display (I2C as well as SPI) on top of GFX library. The only changes that I can imagine are:1 - Wiring (obviously)2 - Headers included on top of the code (SPI, GFX, 1306)3 - (Probably) some constant needed to be defined in the codeI suggest you to take a look at the following code and libraries that are included (and their order) on top of the code:https://github.com/jandelgado/arduino/blob/master/...You can see that it included both SPI and Wire library so my guess is that it should work in both cases. Wire is the underlying library that would be used for I2C communication and the SPI is the one used for communicating over SPI port. I don't have experiences with U8g, but if the sample code in the above link works for you, then you don't need that library at all.

Definitely not directly. Arduino (or any logic level signals like the one used by this breakout board) can't provide enough current to powerful devices (e.g. motors, leds, etc.). You should always try to think about the Arduino part of your circuit as the controlling part. Arduino can decide when to turn something on or off via one of the GPIO pins. You should connect your device (15W LED in you case) to an standalone power supply and place an electronic switch (e.g. a mosfet) between its power source and the LED and whenever you want to turn it on or off, you can just send a signal from Arduino to that switch (for example by setting an output pin to HIGH or LOW) to turn that digital switch on or off. You can easily find a sample diagram on the Internet (here is an example):When you fin...

Definitely not directly. Arduino (or any logic level signals like the one used by this breakout board) can't provide enough current to powerful devices (e.g. motors, leds, etc.). You should always try to think about the Arduino part of your circuit as the controlling part. Arduino can decide when to turn something on or off via one of the GPIO pins. You should connect your device (15W LED in you case) to an standalone power supply and place an electronic switch (e.g. a mosfet) between its power source and the LED and whenever you want to turn it on or off, you can just send a signal from Arduino to that switch (for example by setting an output pin to HIGH or LOW) to turn that digital switch on or off. You can easily find a sample diagram on the Internet (here is an example):When you finished setting up the LED part then you can focus on how enable/disable it using an IR controller. It can be a code just like the one used in this tutorial.

Are you sure you're running this code? This code is using IRremote.h library while your error indicates that there is an error on RobotIRremote library!You may have installed an invalid library on your Arduino IDE.

Hi PrakharIt's not easy to say exactly what's the problem. But based on the error message, looks like a compilation issue regarding variable TKD2. Can you post your complete code or at least more than a single line to inspect it more?

It has been designed originally by Adafruit to work with 3.3V and it's boosted internally to 5V. So it's safe to use the 5V to work with that. I also used the 5V for this tutorial. You can check this link for more information: https://learn.adafruit.com/monochrome-oled-breakou...

Yeah it's quite feature reach. You're welcome ;)

Very useful tips and tricks. Thanks for sharing.

Incorporating magnets in such a smart way is really impressive. Great job :)

Incorporating magnets in such an smart way is really impressive. Great job :)