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D.C input resistance of a BJT transistor in C.E configuration? Answered

what will be resistance across base and emitter of BJT in C.E configuration

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iceng

6 years ago

The base emitter junction is a Non-Linear semiconductor diode.
The DC resistance will change with the current used.

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deepakmuraliiceng

Answer 6 years ago

can u say the range between which the value of input D.C resistance will vary?

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icengdeepakmurali

Answer 6 years ago

What transistor are you using, Then you or I can look-up the data sheet and
pick out the bias that will give you the small signal AC resistance range that
you seek.

Every transistor type has different specifications. Why do you think there are
so many different kinds available ??!?!!

Some serious designers will actually use a curve tracer to get the actual
transistor values for the best circuit function.

CurveTracer.JPG
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deepakmuralideepakmurali

Answer 6 years ago

along with the resistance of the junction will the resistance of remaining parts of base and emitter affect the D.C input resistance?If so by what factor?
Can you explain by assuming your own BJT and base current?

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iceng

6 years ago

PN the well known junction

PN.jpg
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deepakmuraliiceng

Answer 6 years ago

What is that graph(without ohmic resistance)?

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icengdeepakmurali

Answer 6 years ago

Every Electronic Engineer immediately recognizes that base emitter
diode curve tracer VI plot above.

An Ohmic scale is not Linear it is a function of where the bias current
puts the junction into for a current gain condition.
After all BJTs are primarily current amplifiers.
Resistance = Voltage ( X axis ) divided by current ( Y axis ), Really !

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deepakmuralisteveastrouk

Answer 6 years ago

depends on the load in the sense?
Load will be connected across collector and ground(C.E configuration) and what this load has to do with input D.C resistance between Base and Emitter? Can you please explain

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steveastroukdeepakmurali

Answer 6 years ago

Take a look at the current and voltage in the transistor from the load lines: Resistance in the collector is Vcc-Vce/Ic Resistance referred to the base would be Ic/Hfe Vbe ~0.6V if the base is saturated, so Rb=Vbe x Hfe/Ic

Steve

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rickharris

6 years ago

Depends on which way you measure it.

One way almost open circuit the other way - depends.

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rickharrisdeepakmurali

Answer 6 years ago

The base emitter junction is a diode. If you measure the resistance one way it will be open circuit and the other way will depend on the transistor, it's state at the time you measure.

You need to read the transistor theory pages suggested in your other question so you can understand what the transistor does and why.