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Im out of .1uF capacitors! Can I replace them with a different value? Answered

Im building a FM transmitter and the project requires (3) 0.1uF capacitors. But i have none left! Can i replace them with a different value?∫

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sofia lumai

3 years ago

I am out of 1 uF , 10 uF , 470 nF ceramic capacitors. I cannot search in anywhere. Can I replace these with another values? Can some one help me please! I need as soon as possible.

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icengsofia lumai

Answer 3 years ago

Our crystal ball is unable to home in on your circuit schematic diagram, would you please send a picture where you want to do this exchange and include what capacitor values you do have on hand.

BTW piggybacking on someone else's question is not good form, because you cannot award the best answer. Also makes you look too lazy to ask your own question.

QQ--AA.bmp
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jeff-o

7 years ago

Hmmm, maybe you could put two 0.22uF caps in series, or two 0.047uF caps in parallel. That could get you close.

Of course, if those 0.1uF caps are only being used for decoupling (are they connected from Vcc to ground?) then you could chuck the same type capacitor of a larger value (0.15, 0.22) and it should be fine.

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janw

7 years ago

Sometimes you can and sometimes you can it all depends on the circuit.
These 0.1uF apacitors cost really peanuts online so I would just buy some.

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iceng

7 years ago

Those kind of capacitors are usually used to bypass ICs, anything else near that value will do as well.
But if its a part of a tank circuit section, the instructions would surely ask you to measure them because the run of the board 0.1uF capacitor will vary +-20% and that would play ( not well ) with FM.
So we are back to bypass caps.
Your stats say you are nice person,
if you are near Reno Ill give you a hand full of o.1uF caps.

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kelseymh

7 years ago

If you want to do a one-for-one replacement, then the answer is probably "no." It depends on the details of the circuit -- are the caps being used to provide a time constant, or to set a matched impedance, or just to do AC/ripple filtering?

If you have a supply of caps, then you can combine multiple capacitors to get an effective capacitance, just as you can combine resistors. The rules for caps are the opposite of resistors:

In series: 1/Ctot = 1/C1 + 1/C2 + ...

In parallel: Ctot = C1 + C2 + ...

You can play around with arithmetic (or set up an Excel spreadsheet) and find some combination of the caps you have on hand to get a net 0.1µF.

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steveastrouk

7 years ago

Depends on the circuit !!!

Steve