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# Low voltage to very high voltage transformer that can handle as high a current as possible?

I'm looking to convert roughly 5v ac to around 400v or 500v and be able to handle an enormous current. I know very little about transformers when it comes to their current limits. Any help would be appreciated.

## Discussions

Seems like the transformer option is out the window from the responses, would there be a way to bump the voltage up DC-DC?

This is what 5000A is capable of. Look at the 5000A fuse :O

Unless you are photonicInduction-approved transformer, or converter, No. I mean think about it, if you want 500V and maybe assuming 10A output, then you would need 5000W, 1000A 5V on the input. that is a INSANE amount of current, it is simply not practical to deal with those types of currents. I mean even large welding transformers only output like a few hundred amps!

In every practical way - NO. Sorry.

As I asked earlier - You almost certainly have 110 or 240 volts AC available at around 80 amps. Why no start with that, Your still not going to get 1000's of amps though.

It's just the way it works. Your looking to be in superconductor territory.

Do you really really need that sort of current?

The idea is to charge a capacitor bank to a high voltage as quickly as possible

The quickest way: Mains voltage, rectifier, limiting resistor.

Resistor 400/80, or 40 Ohms, charging time for a 1F cap ~40 seconds

You're still stuck with mA, and the conservation of energy. Lets say you can take your 5V at a comfortable current, say 5A and boost it to 500V. You have 25 W of charging power, at 500V, or25/500 or 0.05A.

For a 1F supercap, with a 500V capacity, and limiting the maximum current to 50mA, means your cap will charge in 2.75 hours.

It still uses magnetism and the current to weight is worse !

If this is a CONTINUOUS current, you can't do it. If its an instantaneous current, you can using a capacitor and a charging circuit.

The idea is to use a supercapacitor to charge a capacitor of a higher voltage, the current on the power supply side shouldn't be an issue

To give you a sense of transformer proportional size, these neon light transformers are the best the French nation can make and they produce 7500 VAC at 30 ma and that big one is a 15000 VAC monster about 35 LBs all running on120 VAC 60Hz.

Now you want to go from 5VAC to 500 VAC Enormous current say 200 amperes.

Simply do it by power and weight your 500v x 200a = 100000 VA

REAL WORLD 15000v x o.030a = 450 VA which is 222 times less then your VA and that means 35lbs x 222 => your transformer will weigh about 7,778 LBs......

Why are we still discussing this?

Seems to be quite obvious that it is next to impossible to get 5V supply in the kA range....

Also that it is quite useless to try to go from 5V to high voltage if those currents are required.

Just saying.... ;)

It IS, I've seen them, literally built between 1 inch square bus bars. Practical for this ? No. Ac ? No again....

Voltage up current down, next is your booster efficiency no mater what type, at best 80% efficiency may be as low as 50%.

So at an input of 5 volts 125 to 200 amps, might only get 500 volts 1 amp at output.

take a look at aleator777's instructable https://www.instructables.com/id/Intro-To-Transformers/

Except that's full of wrong. Be careful

500V and an _ENORMOUS_ current (say like 1000A?). Yep. No problem. A one square inch copper rod can handle that. But ow on earth will you generate the hindred fold (500V / 5V) primary current? That's 100000A (100kA) at 5V?! Tell me (and the whole world) how!!

Okay, you found a way to handle KILO-Amperes and bend superconductors to your will - get ready for the next Noble Prices! (Otherwise learn about the basics and ask again)

Won't work with a transformer, maybe with a switchmode power supply but I fail to see why someone needs to go from 5 to 500V.

Transformers convert power from one form to another, they are very efficient machines.

INPUT POWER = OUTPUT POWER

So lets put 10A in at 5V on the primary = 50W

Let take it out of the secondary 50/500 = 100mA.

You can see to "handle an enormous current" on the OUTPUT in this example means you have to have TEN TIMES more current on the primary. It may or may not be possible to GET that current, but, even if it were, the primary resistance would have to be very low.

When you increase voltage you proportionally decrease the current.

You cans see from this that to get a high current out you need a VERY high current in, usually not very desirable.

This perhaps isn't the best way to achieve you ends. If you can it will benefit you to tell us a bit more about your aim. Assuming you will have mains available then your already a long way up towards your 400 volts and at potentially a reasonable high current.