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# Need Geometry Help!!!!!! VERY Urgent!

My school thought it would be a good idea to give me 3 massive projects all due in teh same date (2 days) I finished an enlgish project that involved a table with 300 words and theire meanings and stuff.

Now I'm down to a geometry project, using the Pythagorean theorem (did I spell that right?). The problem is such:

In the triangle ABC, rectangle in C (C=90 ^{o}). a=15 units and c=17 units. Unit=1/2 centimeter

Use the theorem to find the third side.

Well, Im a bit stumped, could anyone help me here? At least how to start it. (As far as i know, the Pythagorean theorem states that a^{2} = b^{2} + c^{2})

help!

## Discussions

wow

can somebody tell me how to make that "squared" number 2 appear?

it's not (A squared=B squared+C squared)

it's........(A squared+B squared=C squared)

see the difference?

btw it's "four centimeters or 8 half centimeters."

I actually found it today. on Microsoft word Its insert>symbol then look for it

oh.. HAHA now i feel like an idiot. thanks though im going to have to make a mental note.

15

^{2}=b^{2}+17^{2}15

^{2}-17^{2}=b^{2}SQRT(15

^{2}-17^{2})=bTell a lie, that doesn't work. The answer you need to use is 17

^{2}- 15^{2}= b^{2}oh wow thank you, it makes sense now! never thought of that!!!! Appreciate the help

It's alright, I've had 2 weeks off so need some maths practice anyway.

Lucky... I get vacation this week, but I don't have math until next year!

Next year?? OK, that's weird - In the UK, students get maths, English and science at least twice every week until they are 16. Up the the age of 11, they get maths and English every day. Even at Uni, if there are core-subject components of a course, they tend to happen every week.

Don't think its an American thing -- most schools don't do "block scheduling", as its called. We have 4 classes a day, each being roughly 90 minutes long. So we end up getting more of the class than if it was all-year. Even then, some math/English classes are all year, but usually just the lower-level classes. Mine was 3/4.

Just as a general hint for the future, you can use a little trick if you get stuck rearranging a formula.

If you take the formula you had, e.g a

^{2}+b^{2}=c^{2}then you can substitute values into a similar formula. For example, I tend to use low values like so:2+3=5

In this, c

^{2}is 5 etc...This is a bit more simple than that confusing formula, so you can quickly work out what works and doesn't, in this case, the formula can be arranged into:

5-2=3

2=5-3 etc..

Then you just substitute the algebraic values back in your rearranged formula.

I actually did that right after you posted

Tell a lie, that doesn't work. The answer you need to use is 17^{2}- 15^{2}= b^{2}Thanks for the tip though, I never thought of using that to help me!

I am in Algebra.

_{Yes, I know, this doesn't help at all.}is algebra below geometry, or is that just in my school, in my school it goes: 7th algebra Geometry Algebra II (I am here) Pre-Calc (I'm taking adv honors next year, yay!) calc then something else So you got all of that pythagorean sutff all right? The main thing I remember from geometry is donald duck in mathmagic land, LOL

Awesome.

why is that awesome?

It's not, it's sarcasm.

That's not sarcasm.

This is sarcasmyea....

awesomeEmotions can't be expressed in a comment

I thought that was italics...

*guh-*.......I....

well, you're no help at all!

I hate trig!