0kiffer360 8 years ago ReplyUpvotec^3+27 addition of cubes (c+3)(c^2+3c+9) Am I reading the problem wrong?

0kiffer360seandogue Answer 8 years ago ReplyUpvoteright, its the formula. i never can rember the correct formula. (c+3)(c2-3c+9) i think.

0seandoguekiffer360 Answer 8 years ago ReplyUpvoteDing!... I guess I'd forgotten that there's a formula for disemboweling a cubic equation. I played the "guess the first term" game...

0NobodyInParticular 8 years ago ReplyUpvote I suspect that you were supposed to memorize the factorizations of the sum of cubes, difference of cubes, difference of squares, and perfect square trinomials. If you memorize these, you will save yourself a great deal of trouble. (a^3^ + b^3^) = (a^3^ - b^3^) = (a^2^ - b^2^) = (a^2^ + 2ab + b^2^) = (a^2^ - 2ab + b^2^) =

0seandogue 8 years ago ReplyUpvotePerhaps start by thinking of it as a disguised quadratic instead of a cubic equation?

## Discussions

8 years ago

With Mathematica.

Answer 7 years ago

(3 + c) (9 - 3 c + c^2)

8 years ago

c^3+27

addition of cubes

(c+3)(c^2+3c+9)

Am I reading the problem wrong?

Answer 8 years ago

No, but your answer is wrong. close, but wrong.

Answer 8 years ago

right, its the formula. i never can rember the correct formula. (c+3)(c2-3c+9) i think.

Answer 8 years ago

Ding!... I guess I'd forgotten that there's a formula for disemboweling a cubic equation. I played the "guess the first term" game...

8 years ago

I suspect that you were supposed to memorize the factorizations of the sum of cubes, difference of cubes, difference of squares, and perfect square trinomials. If you memorize these, you will save yourself a great deal of trouble.

(a^3^ + b^3^) =

(a^3^ - b^3^) =

(a^2^ - b^2^) =

(a^2^ + 2ab + b^2^) =

(a^2^ - 2ab + b^2^) =

8 years ago

Another clue is C cubed = -27

8 years ago

Perhaps start by thinking of it as a disguised quadratic instead of a cubic equation?