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solid state relay information Answered

Do I need to apply voltage to pin 5 for it to switch on chip Vishay VO14642AABTR?

http://www.alldatasheet.com/datasheet-pdf/pdf/443188/VISHAY/VO14642AABTR.html

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steveastrouk

Best Answer 5 years ago

No, to switch the device, turn on the LED on pin 1 and 2.
Its just like any LED, it needs a current limiting resistor.

Pin 5 is an OUTPUT !

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steveastroukjbaker22

Answer 5 years ago

Part of the output circuit. The datasheet clearly shows how it should be wired.

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steveastroukjbaker22

Answer 5 years ago

Look at the circuits that Iceng posted !!! Pin 4 IS used as part of the output in DC cases. Its linked to pin 6.

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jbaker22steveastrouk

Answer 5 years ago

Hope it will work out like this. https://www.circuitlab.com/circuit/99eua9/rc/

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steveastrouk

5 years ago

You have the battery in the wrong way round for the device. Pin 6 should be connected to the positive supply. Pin 4 should connect to pin 6, and pin 5 to the motor, and the motor to the battery -ve terminal.

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jbaker22steveastrouk

Answer 5 years ago

Thanks, I swapped it around and saved what I think you meant.
https://www.circuitlab.com/circuit/99eua9/rc/

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jbaker22steveastrouk

Answer 5 years ago

Okay
https://www.circuitlab.com/circuit/99eua9/rc/

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steveastrouksteveastrouk

Answer 5 years ago

WHOA. Add a nice big diode across the motor ! Put the band end aWAY from the battery.

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iceng

5 years ago

You need to understand MOSFETS have Intrinsic Parallel Diodes

See my picture.

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SSRFET1.png
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icengiceng

Answer 5 years ago

But even though they are as fast as the MOSFET,  I would put a pair
of 1N4006 in parallel in the AC/DC configuration which is half the
current of the plain DC configuration where both fets are in parallel.

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steveastrouk

5 years ago

Link doesn't work. Post the device number.