## Introduction: I Need Your Help. IPT (Inductive Power Transfer)

THIS INSTRUCTABLE IS NOT YET COMPLETE. I have been trying to build a wireless charger but have come across a problem. I have documented what I have done and learnt so far. Hopefully from this you can see my errors and help me out. Please read the last page to see what I think the problem is and suggest any ways to get around this. THANKS**The Project**

I am trying to build a circuit that will allow gadgets that are usually charged by USB to be charged wirelessly. As an example I am reverse engineering an A4tech battery-less mouse. However it is too great a challenge for me and I am seeking help from you. I thought it would be better for me to turn this into a group effort than to ditch the project. I will give a detailed description of what I have built and learnt and hopefully you can tell me where I went wrong.

## Step 1: Background Information

Transferring power wirelessly is reasonably simple. If you think about it, all transformers are wireless. But we want something that's truly wireless. Like the Splashpad (see picture). It is pretty much a transformer with an air core.

The mouse I was talking about (see other picture) in the introduction is exactly the same as the Splashpad it uses induction to transfer power across an air gap. This is the same technology as RFID; in fact it uses this to communicate with the pad. To make our own wireless device we need to know more about induction.

## Step 2: Basic Theory

We need two coils. A primary and a secondary. The primary will be connected to an AC power source that creates an alternating magnetic field spreading out into space to infinity; however as we get further away from the primary coil the strength of the field dramatically decreases. Now, if we hold our secondary coil anywhere in that space an alternating current will be induced. Unfortunately this current is so low that it is too low to do anything useful or should I say too low to even measure. Gigantically low, so low it might as well be nothing. I think you get the point. So the question is; how do we Increase the power that is transferred to the secondary coil?

It is called inductive coupling of tuned circuits (Here is some more detailed information, more tesla coil orientated but more or less the same principles. http://home.freeuk.com/dunckx/wireless/inductive/inductive.html).

We need an AC power source for the primary, any frequency would do, but to make it more efficient we need a high frequency. To explain this think of two solenoids. If we hook up the primary coil to a DC supply. Initially the current will be zero, the current will increase at a decreasing rate due to a magnetic field that is created to oppose the change, once the two reach equilibrium the current reaches a steady maximum (can be calculated by I=V/R) and the magnetic field also becomes constant. This changing magnetic field induces a current in the secondary which produces a magnetic field in the opposite direction. This is just a small blip of current that lasts just for a short period of time. We have just transferred a small amount of power. Now if we did this over and over again we would induce more tiny blips and hence more power. This is why a higher frequency would transfer more power.

The battery-less mouse has a frequency range of about 119kHz to 135kHz, which is what we will use; it is probably a legal frequency???

*The third image I grabbed from a lecture slide, the lecture had no name on it. If someone objects to me taking this slide, please let me know and I'll remove it.

## Step 3: Resonator

So we have a high frequency power source, now we need a primary coil, this coil shouldn't be too large so that it is more like a pad than a brick. It doesn't really matter too much but we want something like the mouse/Splashpad.

To decrease the resistance/Impedance of the primary circuit we need a coil in series with a capacitor. So the final circuit will look something like the circuit on the left in the image below. The capacitor and inductor make something called a resonator. If the capacitor was fully charged and then connected in parallel with an inductor (right-hand side of image) we would get an alternating current flowing through the two components. This is because the capacitor discharges through the inductor, a magnetic field is created. When the capacitor is fully discharged the current stops, the energy of the magnetic field is converted back into electricity; this recharges the capacitor. This cycle then repeats many times. This type of oscillation is called resonance if the reactance's (see next sentence) of the inductor and capacitor are equal. Reactance is the equivalent of resistance in a DC circuit.

Let's take a look at my high school notes book.

## Step 4: AC in Resistors

The current and voltage are in phase

## Step 5: AC in Capacitors and Inductors

The current and voltage are out of phase

The resistance is not easily calculated as AC resistance is affected by frequency, We therefore use a different physical quantity called reactance, it still has the same unit as resistance. The ohm.

It is clear that frequency affects the resistance and hence the current. See second image

## Step 6: LCR (Inductor,Capacitor,Resistor) Resonant Circuit

This is slightly different from the LC circuit mentioned above, but the same principles apply.

The graph pretty much explains how the resistance of a resonant circuit decreases if the reactance's of the capacitor and inductor are equal. The frequency that this occurs at is called the resonant frequency.

(see picture)

Note: the circle diagrams with the arrows are phasor diagrams that represent the magnitude of the quantity at a moment in time. In the resonant circuit above the reactances of the capacitor and inductor are equal and opposite having the effect of cancelling eachother out.

The Whole picture

This theory helps us understand that if the primary and secondary circuits in our wireless circuit are at resonance we increase the effieciency. No power is lost in the inductor and capacitor.

## Step 7: The Circuit (AC/square Wave Generator)

We need to construct a circuit that can produce alternating current at a desired frequency. My first attempt was using a Multivibrator (http://en.wikipedia.org/wiki/Multivibrator). However that didn't work unless it had a separate power supply, whenever I attached the load, the change in current due to a parallel circuit would affect the rate of the multivibrator. It also isn't very accurate because it relies on the accuracy of the values of the capacitors and resistors. Take a look at the page anyway because it is quite interesting to know that the multivibrator can make a flip flop.

Another way would have been to use a comparator as a square wave generator (http://hyperphysics.phy-astr.gsu.edu/hbase/electronic/square.html#c1). The maths looked complicated so I soon discarded that idea.

In the end I decided to use a 555 Timer. We have probably all heard of this universal device. As far as I know it is quite an accurate timing device and is rather simple to use. We are going to use it in its Astable configuration. Below is a small excerpt from a webpage (http://www.kpsec.freeuk.com/555timer.htm) with everything you need to know about it.

## Step 8: Choosing Resistor Values for 555 Timer

We need to choose resistor values that will give us a frequency of about 120kHz. I happen to have a 181K capacitor.

Lets use the formula from the previous webpage to calculate the value of R2 (in the picture below).

(see second image)

This gives us a result of 32407.41. The closest resistor value I have is 33kOhm, which has a value of 32.5kOhm when measured with a multimeter. We will use this more accurate measurement to work out the true frequency of our circuit using the following formula

(see fifth image)

Our true frequency is 119658.12 Hz

The value of R1 has to be about one tenth of R2 to make the mark and space time approximately equal! So, 3.3kOhm

## Step 9: Square Wave Generator

Now we need something that takes this signal and turns it into AC using a DC source. I have come up with various circuits. Below is the original circuit I designed. I first tested this in combination with the multivibrator but it affected the rate of the multivibrator. I thought it didn't work because of this and decided to look at google patents for another idea. Check these out, there's some interesting stuff.

## Step 10: AC Generator

With a bit of research I found many varieties of DC to AC inverters/converters. Many were complicated and so I went back to the drawing board. The circuit below is what I came up with. It uses a voltage divider to create dual voltage power supply. In my case +3V and -3V with a neutral centre tap. How does it work? (see diagram)

We have alternate current through the resistor by the centre tap.

I have tested this and it does work at low frequencies for testing.

## Step 11: Primary Coil

All we have to do now is decide on the coil shape and size and the capacitor that will create a resonant circuit. For testing I have used primary/secondary coils that are of similar size so that they can be wound on the same pipe, just for simplicity. There are many online calculators for calculating inductance (See the external links for some of the calculators I looked at). I decided to use a program called MiscEl (http://www.miscel.dk/MiscEl/miscel.html, its freeware!).

First choose a capacitor and calculate its reactance. Then calculate the required inductance you need to create a resonant circuit. I have used the values I used in my circuit.

(see image)

MiscEl can work backwards. Enter the inductance and the diameter of the coil. It will then give you the number of windings needed to produce that inductance. Make this coil and attach it to the capacitor in series. Ok thats the primary circuit complete. As you may have noticed, all my work has been done on a breadboard. That's because it doesn't work yet. When I get this thing going I'll make all the printed circuit boards and modify this instructable with all the correct values and dimensions. Your help is appreciated.

## Step 12: The Secondary Circuit

As you would have guessed. This circuit is also at the resonant frequency. Using the frequency of the primary circuit we will calculate the value of the capacitor and the value of the inductor. The secondary coil cannot be too large as it needs to eventually fit onto one of our electronic gadgets. Therefore we want a small number of turns. When I originally thought of doing this I was going to use a flat spiral coil. I will do that as soon as I get this working. The final secondary circuit will be all on one circuit board, for ease of production.

Anyway. I have a variable capacitor that I should use in conjunction with a fixed capacitor to allow us to fine tune our circuit. I have a variable radio capacitor with a capacitance of up to 220pf when the two internal capacitances are connected. We do this by connecting the two outside leads (A &O;) of the variable capacitor. Like in the picture below.

We also attach a capacitor in parallel with the variable capacitor to increase the capacitance. I used a green cap with the markings of 104J (100000pf). Using this information we can once again calculate the reactance's and hence the dimensions of the coil using MiscEl.

(see second image)

## Step 13: Finally, the Problem

We can turn on the circuit and see whether we induce a voltage on the secondary coil. Now unfortunately it doesn't work. I have analyzed the mouse and its circuit to find out what the difference is between my circuit and theirs. One significant difference is the voltage across the primary. I measured a voltage of 8V. The voltage on mine was about 0.4 volts. But how is this possible. A low resistance coil with a high voltage. If we apply ohms law we would find that the current would have to be huge. But it's a USB powered device and is restricted by the maximum current the computer can supply. And this current is very low.

This is where I'm stuck. How can I increase the voltage across the primary coil?

Below are some photos of the A4Tech mouse. The secondary circuit of the mouse is exactly like mine, minus the rectifier which I will add later. The primary is similar too, a capacitor in series with the coil. A coil, which has very little turns and a low resistance.

Please, if you are good with electronics and physics. Could you suggest some ways that would make this thing work and point out any errors I have made?

## Step 14: Update 1

Below is a short video clip of what I have built so far . All the plans for the circuitry with the values you see in the video clip are below.

## Step 15: References So Far

This file contains click on links with descriptions.

This file was created on a mac with opera. If it doesn't open try opening it with a text program like notepad or textedit

## Step 16: A Part IV Project Report on 'An Inductively Coupled Universal Battery Charger'

I know its long, but if you're interested in the power transfer part its definately worth reading.

Thank you to Cerincok who brought this to my attention!

## Step 17: Microcontroller Info

If you're interested in using a microcontroller to generate the signal.

See PDF's

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## 183 Comments

send me wirless power transfer project circuit diagram input ac 230v 50 HZ and secondary coil side 12v 40 khz or other valid circuit daigaram on this mail haylaz7@hotmail.com or look www.brautfrisurens.com project category...

Please send me wirless power transfer project circuit diagram input ac 230v 50 HZ and secondary coil side 12v 40 khz or other valid circuit daigaram on this mail

nirajmane9@gmail.com

Hi , i want to build wireless transfer coil antenna to get 12 v and 5 v , how do i calculate the number of winding of the coil and the diameter and thickness of the coil , whats the right formula to be calculate to get the right coil please.thanks

I've the same doubt..

So do I :p

Provided you have matching tuned LC circuits, you need to excite the primary coil with an alternated supply. If the magnetic field don't alternate you can't pick up the power on the secondary coil. Only some weak spikes caused by the induction feedback... From what I saw, I think that your problem is on the excitation circuit. A simple 555 can't do it. Also, the problem is not about using sine or square waves... Just alternate it from negative to positive and you will have a good surprise :-)

Try using a small micro controller (e.g. arduino is easy) and an h bridge to drive a coil with a square alternated signal. You can do this with a 555 and some gates and the fets... But will require more know how.

Have fun :-)

Regarding your question about voltage across the primary, I assume you mean a.c. voltage. The drop across the primary is proportional to the impedance of the primary at the signal frequency. This will depend partly on the reflected impedance from the secondary. And, I couldn't find the refrence to your operating frequency, but check the specs on your meter to see if it measures at that frequency.

One solution If your portable device can be kept in one position during power transfer and it does not need to be movable during transfer like the mouse, then you might want to consider taking a ferrite core and saw it in half (probably need a carbide blade for this). On one half wind your primary, on the other half wind your secodary. Mount the halves of this transformer in their respective devices so that you can re-contact the two halves by placing one device on top of the other.

This way, using a ferrite core, you would have better coupling and you could operate at a lower frequency than with an air core transformer.

interesting I dont know how I could be of help private message me if you have any thoughts on this

I think you would be better off using a Crystal Oscillator instead of a 555 based timer. For one, you'll be generating a much much higher frequency than a 555 could. They're limited to about 500Khz depending on manufacturer. Check out http://www.vk2zay.net/article/262

Alan Yate's site has a very nice outline for this entire project. Highly recommend checking his stuff out. About higher frequency, the higher your frequency the less inductance you'll need.

I'm just new to the electronics world so if anyone could answer me. I have a 1k and 10 ohms resistor, and I need to have a default of 1 minute on 555 timer, did I have the right value? I would appreciate any reply. thank you