Reduce the Temperature of Solenoid Valve for Continuous Driving
Intro: Reduce the Temperature of Solenoid Valve for Continuous Driving
For most application driving the solenoid valve we just apply the proper voltage to the coil. But we found the coil became very hot for continuous driving for a while.Here I had a solution to reduce the power consumption when it driving It worked like this,when the power DC24v apply it and the capacitor charging for large current and the coil same get the current and the valve activate, capacitor charging for a while the charging current reduced and the voltage across the coil devide by the resistor low down the power of the coil and the coil get only a little heat.
STEP 1:
First step you should test the solenoid valve "holding"voltage and "inrush" voltage. Connect the solenoid valve and adjust the voltage from 0v to 24v and you should hear the activated noise "ka". For this example it about 20v, it means the voltage must be large than 20v the valve activate.(This we call holding voltage). And then turn the voltage from 24v to 0v, same as before you can hear another "ka" noise, it means de-activate (or released). For this example it about 3v.(This we call inrush voltage)
STEP 2:
Second step we measure the coil resistance use the multimeter. For this example it about 66 ohms at coil resistance.
STEP 3:
Decide the ceramic resistor, There is a voltage devider of coil and ceramic resistor. So we choice the 220 ohm resister and make the voltage across the coil about 5.5v large than 3v , It means the valve always activate at 5.5v(because it large than 3v), but the coil consumption less power (less heat).
Attention: this method only for DC driving valve, (for AC driving valve it maybe use TRIAC or SCR structure)
Attention: this method only for DC driving valve, (for AC driving valve it maybe use TRIAC or SCR structure)
14 Comments
Billownious 2 years ago
tendo stated:
"Finally I’ve find a working solution in my case. I use the regulated DC
12 2A power supply, 4 ceramic resistors 10 Ohm x 5W (in series) and 1
electrolytic capacitor 10000uF/35V (6600uF is minimum in my case). In
this case current I=0.26A (by multimeter) is enough to hold my coil in
open position, voltage drop on a coil was 0.95V, total voltage drop on 4
resistors was about 10.5V.
Testing: after 14 hours of continuous
operation the coil was absolutely cold (and still in open position),
resistors was warm (so I can freely hold my fingers on all 4 resistors).
So, thank you once more for the help!"
Thank you for anything that helps.
J
tendo 11 years ago
paiwayne 11 years ago
Here you NO success means the solenoid deactivate, it mean coil current not enough(very low resistance of coil)to activate , so the capacitance of capacitor should be larger than my job.
tendo 11 years ago
Testing: after 14 hours of continuous operation the coil was absolutely cold (and still in open position), resistors was warm (so I can freely hold my fingers on all 4 resistors).
So, thank you once more for the help!
Diazovitch 3 years ago
tendo 11 years ago
paiwayne 11 years ago
eyyong 7 years ago
how you calculate and select the resistance and capacitance? Which fomula you use? It would be great if you could share us this detail
paiwayne 11 years ago
ErikA45 6 years ago
Interesting article. But the resistor calculation can be much simpler:
1. measure current with coil in hot state (usually 30 to 50% lower than "cold" current)
2. reduce voltage of the power supply until the coil drops out (usually 10% of nominal voltage).
3. Multiply this voltage by at least factor 3 (safety margin); I would take this value, or at least half the nominal supply voltage: the "actual voltage"
4. Measure the current at that "actual voltage"
5. R = (difference between nominal and actual voltage) / actual current
6. Power dissipation in resistor: P = R x (square of current); choose a resistor at least twice that value.
gunnucool 7 years ago
I have a AC 220v Solenoid Valve. I need to know how to go about reducing the temperature as it would be turned on for 4-5 hours every alternate days.
tendo 11 years ago
paiwayne 11 years ago
tendo 11 years ago