## Calculating Drag When Firing Potato Launcher and Design Specifications

I'm interested in making a pneumatic potato launcher, I've found plenty information on that but I want to hit a target 255 meters away at an angle of 45 degrees. I calculated that I would need an initial velocity of approximately 50 m/s without wind resistance. The object being launched is an average sized potato under normal weather conditions. With wind resistance, what initial velocity will be required to hit the target? Please explain the process by which you came to the answer so that I may use the same method in future endeavors with different angles and distances. Also, just how much pressure would be required to launch a potato and achieve that speed, and to what specifications would the launcher need to be built i.e. how large the gas chamber will need to be, length of barrel, etc...

active| newest | oldestnotsimple, but it is tractable. If this is a classroom project and you expect us to do your work for you, then you're hopefully out of luck.First, the air resistance issue. Potatoes are irregularly shaped, and each one is unique, so trying to get an exact value is silly.

If you have access to a small wind tunnel (I don't find an I'ble to make one, so check Google or Wikipedia), then you can measure the drag yourself with a sample of different potatoes, and take an average (or largest value).

Alternatively, you could do the calculation by assuming the potato is a smooth sphere, and looking up the answer. Either way, keep in mind that drag is proportional to velocity, so if you just take the drag result and increase your launch velocity, the resulting drag will be even higher. The process does converge (obviously :-), but might need to iterate your calculation a couple of times.

Second, pressure to get launch velocity. This is trivial arithmetic based on definitions and unit conversions. What is the cross sectional area (A) of your potato and launcher (they have to be the same, obviously)? Let P be the unknown pressure; then the total force on the potato is just F = P*A (with consistent units).

Given the mass (m) of your potato, the initial acceleration (a) is found from F = m*a. The length of the launcher (l) determines how long the acceleration is applied (l = 1/2 a*t

^{2}), and then v = a*t gives you the muzzle velocity.Algebra (or calculus, if you want to take into account the pressure drop as the potato moves down the barrel) is your problem, not mine.

Without having an immediate clue how to calculate it, isn't the pressure issue more complex than you make out? As the potato moves up the barrel, the volume "behind" it will increase, so the pressure drops as the potato moves.

And what about friction between potato and barrel? That will vary wildly with fit and moisture content...

I suppose what I'm saying is that this is one of those problems I would prefer to solve by trial and error.

...Kelsey!howto solve it.It introduces at least three broad physics concepts, along with the general problem-solving technique of simplifying approximations. That should be more than enough for Mike714 to go the rest of the way on his own.