1: The common use of batteries instead of a more permanent power source
2: The intensely bright spots which LEDs often produce
I based some of my design off of other projects and modified the points I wanted to improve on, this resulted in the Bawls Blue Crystal LED Light seen bellow.
Remove these ads by
Signing UpStep 1: Parts and Tools
For this project you will need the following;
Tools
-Soldering iron
-Solder
-Hot glue gun
-Heat gun (or a lighter)
-Drill
-Glass drill bit ( Black and Decker Model # 16903 )
-Wire cutters
-Wire stripper
Materials
-Some scrap wire
-A resistor (Proper resistance to match your LEDs)
-Heat shrink
-Eight LEDs
-Power supply
-Bawls bottle
-Empty glass bottles (3 or 4 empty Snapple bottles should do)








































Visit Our Store »
Go Pro Today »




i made a green and a blue one.
So, for example if we had a 9 volt power supply and LED’s which can run at 700mA we would solve for resistance as follows.
v = ir
plug in our values
9volts = (700*10-3) amps * (r) ohms
Solve for r
r = 9/(700*10-3)
r = 1.29*103 ohms = 1290 ohms = 1.29 kOhms
any value within 5% of your calculated value will work. Most resistors can vary from 5 to 10 %.
Note that in this example we are assuming that the wire used and the LED’s used have no resistance. This will very closely emulate the conditions of the small circuit you will be building.
If you have more questions let me know.
-Michael I
Input voltage - Desired Output Voltage / Current being pulled in amps = Ohms
so 7.5vin 3.2 desire 20mA power consumption
you would use 215 ohm resistor
ifound some resistors laying around in my drawer today, and as i was reading the colors, they came out as 470Kohm, 220Kohm, and 10Kohm resistors. thats over 100,000 ohm resistors!! help!
i have a 125v power cord and 7 very very small LED lights. about, 10v or 8v. help =(
Use the rules;
when in series Requiv. = R1 + R2 +R3...
when in parallel 1/Requiv. - (1/R1) + (1/R2) + (1/R3).....
Hope this helps,
-Michael I