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IDENTIFY THE ANODE/CATHODE of LED's

Picture of IDENTIFY THE ANODE/CATHODE of LED's
IDENTIFY THE ANODE/CATHODE of LED's



While referring to any schematic involving led's we sometimes get confused with the identification of the terminals. So for identification , led’s comes with a unique way to identify its terminals as Anode or Cathode. Sometime the diode symbol creates confusion too.Identifing a LED's the cathode and anode of a led is very easy by looking inside.
LED's or Light Emitting Diode's don’t come with any labeling on it to identify Cathode(-ve,GND) or Anode(+ve).

I hope the figure below can solve this problem of identification.


Notice the picture carefully and compare it with the LED diode symbol, that should tell which one is –ve and +ve terminal. As they have to be crystall clear to glow so they don’t have any labeling on it , so the only way to know is either to test it with a multimeter or by carefully observing inside the led . The larger end inside the led is -ve and the shorter one is +ve, that is how we find out the polarity of a LED






Save this picture for reference.


NOTE: I took this picture myself from my camera , Please Do not mind for image clarity ,so i have put some labellings also .



THANKS FOR READING

RON

Rakesh Mondal



www.rakeshmondal.info

CATHODE AND ANODE OF LED



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xman22 years ago
Thanks for the info
Doc_Cottom4 months ago

I just learned something.... do not use super glue to hold LEDs in place. It does something to the plastic the LED is made of, and renders it ruined.

dannystaple10 months ago
You could also have mentioned that the cathode has a flat side on many round LED types.
kelvinmead1 year ago
just a shame that you hold the led the wrong way around to the circuit symbol.

this would make this even less confusing!
ron.rakesh.mandal (author)  kelvinmead10 months ago
Yeah i did hold the circuit in the either direction, sorry about that , But you see there is also + and - Symbol to make life easy. :) . Plus I don’t THINK its such big issue for me being ashamed of, as you attempt to project here . anyway thanks for an attempt and comment . :) ;-)
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