As you know there are several instructables on building Bike Lighting systems ,but , hey i wanted to post my own .
After a couple of hours searching instructables ,I haven't saw a proper Bulb-Led conversion , i've just saw some spam or ones with incomplete instructions .
Now i will show you how to retrofit an LED array into a Regular Light bulb , which i think is brighter cleaner , and lotsa times cooler .
As a Bonus i used this LED array in my Bike's Dynamo, Voila, Much more output and half the Power .
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Signing UpStep 1Materials 'N' Tools
The List:
Quantity---------Description
3-5 White Ultra-Bright LEDs (mine were 4900mcd)
1 Used, Burnt or Spare Screw-type Bulb
5-10 CMs(2-5inches)of Small Gauge Wire (mine came from an IDE cable,which is 26AWG)
1 Small Piece of Scrap circuit board (mine had a Dotted design,which is pretty Common)
Tools
-The Usual Soldering Equipment ( Soldering iron , Solder , Helping Hands, Sponge ,Etc)
-Needle or fine tipped Pliers (mine are rusty, That's Why i used my Multi-tool)
-Small Cutters
-A round file
-Hobby knife (i used A hobbico body and a X-acto blade)
-Hot glue and hot glue gun
(Not shown but handy to have )
-A fine tipped Permanent marker
-6 Volt supply and alligator clips
-A Small alligator clip
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What I can say from my perspective may not be the Real answer ,
the problem , i'm not quite sure, it's thet the dinamo doesn't produce enough current to light every thing properly , what could be happening ( which i think impossible due to the air flowing around the dynamo ["air friction] )It's that the coils from within the dynamo produce some heat and it affects the energy production , OR the array doesn't properly convert the current to light .
May I ask , is everything connected properly ?
is the resistor in?
how did you made the LED wiring?
and Thanks BTW
"(and respecting the ohm's law (volts by amps = Watts)) a single 1/2 ohm resistor will do easily the job"
Umm.... how to explain, basically, that isn't how it works... If you need more information, PM me and I'll explain in more detail.
-gamer
The people already familiar with LEDs will know how to find the positive lead etc. but a simple project like this might be a good introduction to working with LEDs so a quick note about "current only flows one way, the longer lead is the anode, we want to wire in parallel" etc.
I'm not sure where you got the 75 from- you appear to be multiplying a voltage by something to get a resistance. Surely the equation you want is voltage / desired current = resistance? (Unless your LEDs want 1/75 A = 13mA...)
Voltage multiplied by current gives you power- I think you wanted voltage divided by current, which gives you the resistance.
My calculations give 2.6V divided by 0.075A = about 35 ohms. (Remember milliamps are not a base unit, so you should convert to amps by dividing by 1000 before performing calculations with other units). As you are using 200 ohms your LEDs won't burn out, but they are not running as brightly as they could be. This online LED calculator agrees that if you are using a single resistor it should be around 35 ohms (rounded up to 39 as the closest common value and allowing for 5% tolerance).
Hope this clears up what I meant.
I think i did the Equation bad ,
Resistance = Voltage divided by Current right ,
The E-calculator gave 33 ohms ,
thanks again PKM