9V Beautiful Small Lamp

this is smalest beautiful lamp that I have buildet,and It takes simple parts to build it

Step 1: Part List

Part list is:
1.Dead 9 volts batery
2.led diode
3.resistor 100 ohms
4.glue

Step 2: Conect the Parts

1.First you need to empty the dead batery,and make holes.then painted in any color,put in the led inside and fill with glue.
2.conect the resistor with the led diode,and conect to the top part of the batery just like on the picture

Step 3: Fill With Glue

Fill with glue the bateru box,and dont forget to put the led diode to bottom of the batery box

Step 4: Finish

This is yours smallest 9 volts lamp,ENJOY

Comments

[raykholo]

i agree that it is very nice, but it could be smaller also, it might be a good idea to use fiber optics or flexible light pipes if u want to equally distribute light to the upper holes

[macobt]

What is this<this is my instructables,not forum for arguments,J have use 100 ohms and my lamp works fine,maybe I am wrong about resistor,than use 220 ohms and problems is solved. regards macobt

[Berserk87]

people learning and talking on the internetz!?! O MY! theres a difference between an argument and a discussion. I was concerned about the about of current you were putting through the led, but it appears it should be fine. at least we know how to use the "reply" button. ;)

[Berserk87]

your using a 100ohm resister with a 9V battery.....WOW. you are going to burn that led out pretty quickly. you should be using something closer to a 1K ohm resister, 10X what your using right now.

[code_e]

Actually, 100 ohms is about right for a white LED, which is what the project appears to be using. Even a lower power LED rated for something like 2.5V @ 20 mA would only need 300 ohms. How did you come up with the 1K ohm figure?

[Berserk87]

http://www.techlib.com/reference/batteries.html

typically V/R=I, but i didnt realize that the 9V will only put out 15mA.

Where the person using any other power source, that resistor wouldnt be doing much at all.

[code_e]

A 9V battery can deliver a lot more than 15 mA. A fresh one can supply a few amperes for a short amount time; more than enough to burn up an LED. The chart in your link shows the typical drain batteries might experience in use, not their rated output.

The way to calculate the series resistor value for an LED, as in this project, is:

(supply voltage - LED operating voltage) / required LED current = R in Ohms

White LEDs usually operate around 3-4V. Assuming it draws 40 mA, you'd need a resistance of 125-150 Ohms. In this case, a little less is okay because 9V alkalines are fairly "puny" and the voltage will drop off rapidly.

[Berserk87]

ultra bright leds are, by datasheep, maxed at 25ma, but ive seen them at ~30ma. ~40ma+ isnt going to destroy the led, but its going to have a much decreased life span. if he uses a bigger resister, his led would be just as bright and last much much longer.

[code_e]

The 40 mA number was just an example and LED specs do vary. 100 ohms is in the ballpark. You have to remember the battery's internal resistance and state of depletion will have an effect on terminal voltage under load too. Going by Duracell's product data...

http://www.duracell.com/oem/Pdf/new/MN1604_US_CT.pdf

...an alkaline 9V would only deliver about 8V in this circuit after approximately 12 hours use. Then 7V after 24 hours, etc.. A 100 ohm resistor is a good compromise between somewhat initially overdriving the LED and maintaining light output as the voltage falls off.

p.s. "datasheep"??

[Berserk87]

ya datasheep.

[code_e]

lol, that actually would be a good name for some product. I don't know what, but it's catchy.

[duck-lemon]

That is very awesome man, and even better given i have all the parts less than 1 meter away from me. Great work 5/5 -Duck

[macobt]

how I am gona burn the le, when 9 volt batery dont have much ampers,and you see that the lamp works.