Unpublished!​

Unpublished!

Comments

[OngE2]

helo sir, i want to ask why my result is negative value when i near to red object with my sensor?

[kartik00013]

its good to see an Indian doing arduino and by the way I am also an Indian .

[GerardoM21]

// Define colour sensor LED pins

int ledArray[] = {2,3,4};

// boolean to know if the balance has been set boolean balanceSet = false;

//place holders for colour detected

int red = 0;

int green = 0;

int blue = 0;

//floats to hold colour arrays float

colourArray[] = {0,0,0};

float whiteArray[] = {0,0,0};

float blackArray[] = {0,0,0};

//place holder for average int avgRead;

void setup(){ //setup the outputs for the colour sensor

pinMode(2,OUTPUT);

pinMode(3,OUTPUT);

pinMode(4,OUTPUT); //begin serial communication

Serial.begin(9600); }

void loop(){

checkBalance();

checkColour();

printColour(); }

void checkBalance(){ //check if the balance has been set, if not, set it

if(balanceSet == false){ setBalance(); } }

void setBalance(){ //set white balance

delay(5000); //delay for five seconds, this gives us time to get a white sample in front of our sensor

//scan the white sample.

//go through each light, get a reading, set the base reading for each colour red, green, and blue to the white array

for(int i = 0;i<=2;i++){

digitalWrite(ledArray[i],HIGH);

delay(100);

getReading(5); //number is the number of scans to take for average, this whole function is redundant, one reading works just as well.

whiteArray[i] = avgRead;

digitalWrite(ledArray[i],LOW);

delay(100); } //done scanning white, now it will pulse blue to tell you that it is time for the black (or grey) sample.

//set black balance delay(5000);

//wait for five seconds so we can position our black sample

//go ahead and scan, sets the colour values for red, green, and blue when exposed to black

for(int i = 0;i<=2;i++){

digitalWrite(ledArray[i],HIGH);

delay(100); getReading(5);

blackArray[i] = avgRead;

//blackArray[i] = analogRead(2);

digitalWrite(ledArray[i],LOW);

delay(100); } //set boolean value so we know that balance is set

balanceSet = true; //delay another 5 seconds to allow the human to catch up to what is going on

delay(5000); }

void checkColour(){

for(int i = 0;i<=2;i++){

digitalWrite(ledArray[i],HIGH); //turn or the LED, red, green or blue depending which iteration

delay(100); //delay to allow CdS to stabalize, they are slow

getReading(5); //take a reading however many times

colourArray[i] = avgRead; //set the current colour in the array to the average reading float

greyDiff = whiteArray[i] - blackArray[i]; //the highest possible return minus the lowest returns the area for values in between

colourArray[i] = (colourArray[i] - blackArray[i])/(greyDiff)*255; //the reading returned minus the lowest value divided by the possible range multiplied by 255 will give us a value roughly between 0-255 representing the value for the current reflectivity(for the colour it is exposed to) of what is being scanned

digitalWrite(ledArray[i],LOW); //turn off the current

LED delay(100); } }

void getReading(int times){

int reading; int tally=0; //take the reading however many times was requested and add them up

for(int i = 0;i < times;i++){

reading = analogRead(0);

tally = reading + tally;

delay(10); } //calculate the average and set it

avgRead = (tally)/times; }

//prints the colour in the colour array, in the next step, we will send this to processing to see how good the sensor works.

void printColour(){

Serial.print("R = ");

Serial.println(int(colourArray[0]));

Serial.print("G = ");

Serial.println(int(colourArray[1]));

Serial.print("B = ");

Serial.println(int(colourArray[2]));

delay(2000); }

[ankur sharma]

explain me the connection

[diy_bloke]

Great, but your explanation is not entirely correct as LDR's dont distinguish in wavelength. What is basically happening with these sensors is that when e.g. pointed at a red object there will be hardly any reflection of the green and blue and the LDR sees that as 'less light'

[gearup500]

I think this is cool, although I can't see the video from my tablet. I think it's my tablet and not your video, though. XD