Homemade RCA Attenuator

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Introduction: Homemade RCA Attenuator

This project arose from the fact that I had too much gain in my audio system, and I needed a practical solution without modifying the PCB circuit.

The problem can be solved using an RCA (in-line) attenuator, but since a new one can be quite expensive, around 30-40 € or even more, so I decided to make one by myself.

Step 1: Preliminary Informations

There are very simple gadgets that can be used for audio purposes with great results. These are passive attenuators. They are very simple objects based on a resistive partition housed in male-female RCA connectors and can be used in particular when there are differences in sensivity between the source (CD player, preamp, etc.) and the amplifier.

Despite the simple construction scheme, as I said before they can be quite expensive in the market.

_____________________________________________________


Before proceeding further, we have to remember that the audio signal can be distinguished substantially in two categories:

.

1) balanced circuit

2) unbalanced circuit

.

The main difference between the two is that one is represented by an unshielded cable while the other does not. However, in reality the common RCA cable we use every day is made up of two conductors, one positive and one negative that also performs the shielding function against interferences (provided that is not too long).

So, that to whom we will be paying attention is the latter (SEE IMAGES).

Step 2: Part List and Tools

The following components can be purchased at any electronics store or via Ebay:

.

-2 Solder RCA Female Connectors (1 black + 1 red)

-2 Solder RCA Male Connectors (1 black + 1 red)

- 4 Metal film resistors (1/4 Watt): one couple of 6.9 KOhm, the other couple of 4.7 KOhm

- Aluminium tube

- Insulating tape

- Heat-shrink tubing

- Electric wire

- Cyanoacrylic glue

.

Tools to be used for operations: scissors, tin welder, tin wire,metal saw.

Step 3: Calculating the Resistors

First of all, I'm going to show the formulas relating a typical unbalanced circuit; in other words I'm speaking of the L (or L-pad) attenuator formula (SEE IMAGE).

This will help us to choose the correct value of the two resistors.

There are many on-line calculators, so the the task can be facilitated.

For my purposes, since I wanted a 10 dB attenuation, via the on-line calculator I found the following resistance values (relative to an input impedance of 10 KΩ):

.

Ra = 6838 Ω (nearest commercial value = 6.9 KΩ)

Rb = 4625 Ω (nearest commercial value = 4.7 KΩ)

.

Step 4: How to Build: Part 1)

The outer casing consists of two pieces of an aluminum tube that can be purchased in any hardware store.

I bought one one meter long tube and with a diameter just slightly greather than the RCA internal screw. Then I cut two equal pieces of 4-5 cm long each.

It is important that the piece is not too short to ensure that the male/female connectors are not close to each other and that there is enough space for the two resistors. Then two wires (2-3 cm in length) are connected between the resistors and the terminals of the RCA connector.

The two pieces can then also be painted at will (as I did, by means of spray paint) or left to its natural aluminium color.

Step 5: How to Build: Part 2)

After unscrewing the male / female RCA connectors, the two resistors, respectively 6.9 KOhm and 4.7 KOhm, are soldered on. The first to the signal pin while the second in parallel from signal to ground pin.


You can choose the female connector for this operation, but the reverse is also fine. It is advisable to cover bare wires and resistors with shrink tubing and insulating tape.

After this operation, the two resistors are interwoven and slightly soldered each other. Furthermore, at the end of the ground pin there is a bit of resistance wire (SEE IMAGES).


At the end of the previous resistors, two electric wires (2-3 cm long) will be soldered and will then be connected to the ends of the other connector.

At this point, the screw of each RCA connector is wound with the insulating tape so that it can fit perfectly inside the aluminum tube. A little of cyanoacrylic glue guarantees the seal of the connector to the tube.

Once the operation is done on one, the next one will be to solder the wires to the terminals of the other connector. Finally, the second screw of the connector is fastened to the tube, always with the help of a little glue.


The end result is the one in the last picture.

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    13 Comments

    0
    jmsuter
    jmsuter

    Question 1 year ago on Step 5

    How do I calculate R value for a balanced signal attenuation?

    0
    slimtender.
    slimtender.

    Answer 1 year ago

    Hi, you must use the H-pad being specific for balanced lines. If you have quite similar input/output impedances you'll choose R1=R2=R3=R4=1/2Z*(K-1)/(K+1) and R5=R6=Z*K/(K^2-1) with K as described above.

    attenuators-attn28.gif
    0
    jmsuter
    jmsuter

    Reply 1 year ago

    Hi Slimtender
    My CD player analog output Z rated at 120 R and my amplifier input Z = 20k for balanced input?

    0
    slimtender.
    slimtender.

    Reply 1 year ago

    Hi, unfortunely when impedances are mismatched the latter is not good you shoud use the O-pad (that is a symmetrical L-pad) like in the the schematic under.
    For exemple, for you -12dB attenuation you'll choose R1=2200 ohm and R2=1000 ohm. For -18dB, R1=2200 ohm, R2=390 ohm.

    attballpad.jpg
    0
    DukeElsner
    DukeElsner

    Question 3 years ago

    Is there a simple formula for calculating the apparent load impedance seen by the source? In my case I'm trying to maintain an input impedance of 10K ohm or greater to my CD player, while cutting its output voltage by over half. My preamp claims to have a impedance of 100K ohms.

    0
    slimtender.
    slimtender.

    Answer 2 years ago

    Sorry for late reply...in reality the formula doesn't change. You still need a L-pad matching to the 100k of your preamp, with rule of thumb 1:10 for Zs:Zl, so ideally R1 (series resitor) of 5.6K shunted with R2 of 10K should work. So you can have a -6dB attenuation if you want half voltage.

    0
    elastic media
    elastic media

    Question 3 years ago on Step 5

    would a variable resistor be a good idea? I'm thinking of getting an attenuator for an audio recorder plugged into a PA for live sound, but I don't know how many db I need. Maybe I need 10db or 20db - or something else. Would that make sense? It would likely be less compact, but that is not important to me.

    0
    slimtender.
    slimtender.

    Answer 3 years ago

    Hello, yes you can also a variable resistor. Or better what you could do is building a variable attenuator through something like this (see link), where for every wheel with pins (upper and lower) you have to connect both R/L signal and ground wires

    0
    swander
    swander

    Question 4 years ago on Step 5

    can I make a variable attenuator with a 20K potentiometer in place of the 2 resistors? I would basically be "turning down" a 10K ohm 6.3kHz input test signal to a cassette deck input to a known value, ie. -10db (0.25V) for tuning the input levels.

    0
    slimtender.
    slimtender.

    Answer 4 years ago

    In reality the potentiometer hasn't a linear behaviour and it could not work. An alternative could be the DIP switch like in the photo, so you can select up to 4 values for channel.

    dip-switch-8-main-big.jpg
    0
    Luke Wilson
    Luke Wilson

    5 years ago

    That's really cool!

    0
    slimtender.
    slimtender.

    Reply 5 years ago

    Thanks Luke!