Python - Calculate Distance to an Object Using Triangulation With Trigonometry

print ("This program will calculate Distance to Object using Triangulation with Trigonometry.")

import math

###  Formula for calculating the Distance using Triangulation with Trigonometry:
#  DistanceToObject = (DistanceBetweenTwoPoints * sin(AnglePointOne) * sin(AnglePointTwo))/(sin(AnglePointOne+AnglePointTwo) )
###############################################################################

# Enter the DistanceBetweenTwoPoints, AnglePointOne, AnglePointTwo


ContinueCalculations = "y"

def CalculateDistanceToObject():
    print ("Calculating the Distance to an Object.")
    # Enter the DistanceBetweenTwoPoints
    DistanceBetweenTwoPoints = float(input("Enter the Distance Between Two Points: ") )
    # Enter the AnglePointOne
    AnglePointOne = float(input("Enter the Angle at Point One: ") )
    # Enter the AnglePointTwo
    AnglePointTwo = float(input("Enter the Angle at Point Two: ") )

    # Convert degrees to radians
    # Python trig functions take radians
    # Use math.radians() function to convert degrees to radians
    AnglePointOneInRadians = math.radians(AnglePointOne)
    AnglePointTwoinRadians = math.radians(AnglePointTwo)

    # Calculate the top of the fraction
    TopOfFraction = (DistanceBetweenTwoPoints * math.sin(AnglePointOneInRadians) * math.sin(AnglePointTwoinRadians) )
    print ("Top of Fraction is: ", TopOfFraction)
    
    # Calculate the bottom of the fraction
    AngleSum = AnglePointOne+AnglePointTwo
    AngleSumInRadians = math.radians(AngleSum)
    BottomOfFraction = (math.sin(AngleSumInRadians))

    # Calculate the fraction
    DistanceToObject = TopOfFraction/BottomOfFraction

    print("The Distance to Object is: ", DistanceToObject)

while (ContinueCalculations=="y"):
    CalculateDistanceToObject()
    ContinueCalculations = str(input("Would you like to continue to calculate the Distance to Object? (y/n): "))

print("==================================")
print ("Thank you to www.MapleSoft.com for assistance with this formula.")