DIY LED-photometer With Arduino for Physics or Chemistry Lessons

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Hello!

Liquids or other objects appear colored because they
reflect or transmit certain colors and in turn swallow (absorb) others. With a so-called photometer, those colors (wavelengths) can be determined, which are absorbed by liquids. The basic principle is simple: with a LED of a certain color you first shine through a cuvette filled with water or another solvent. A photodiode measures the incoming light intensity and converts it into a proportional voltage U0. This value is noted. Thereafter, a cuvette with the liquid to be examined is placed in the beam path and again measures the light intensity or voltage U. The transmission factor in percent is then simply calculated by T = U / U0 * 100. To get the absorption-factor A you just have to calculate A = 100 minus T.

This measurement is repeated with differently colored LEDs and determines in each case T or A as a function of the wavelength (color). If you do this with enough LEDs, you get an absorption curve.

Step 1: The Parts

For the photometer you need the following parts:


* A black case with the dimensions 160 x 100 x 70 mm or similar: housing

* An Arduino Nano: ebay arduino nano

* An operational amplifier LF356: ebay LF356

* 3 capacitors with a capacity of 10μF: ebay capacitors

* 2 capacitors with C = 100nF and a capacitor with 1nF: ebay capacitors

* One voltage inverter ICL7660: ebay ICL7660

* One photodiode BPW34: ebay BPW34 photodiode

* 6 resistors with 100, 1k, 10k, 100k, 1M and 10M ohms: ebay resistors

* an I²C 16x2 display: ebay 16x2 display

* a 2x6 rotary switch: rotary switch

* a 9V battery holder and a 9V battery: battery holder

* a switch: switch

* Glass cuvettes: ebay cuvettes

* LEDs with different color: f.e. ebay LEDs

* a simple 0-15V power supply to power the LEDs

* wood for the cuvette-holder

Step 2: The Circuit and the Arduino-code

The circuit for the photometer is very simple. It consists of a photodiode, an operational amplifier, a voltage-inverter and some other parts (resistors, switches, capacitors). The principle of this type of circuit is to convert the (low) current from the photodiode into a higher voltage, which can be read by the arduino nano. The multiplication-factor is determined by the value of the resistor in the feedback of the OPA. To be more flexible I took 6 different resistors, which can be chosen with the rotary switch. The lowest "magnification" is 100, the highest 10 000 000. Everything is powered by a single 9V battery.

Step 3: First Experiment: the Absorption-curve of Chlorophyll

For the measuring procedure: A cuvette is filled with water or another
transparent solvent. This is then placed in the photometer. The cuvette is being covered with a light-tight lid. Now set the power supply for the LED so that a current of about 10-20mA flows through the LED. After that, use the rotary switch to select the position at which the output voltage of the photodiode is around 3-4V. The fine tuning of the output voltage can still be done with the adjustable power supply. This voltage U0 is noted. Then take the cuvette containing the liquid to be examined and place it in the photometer. At this point the voltage of the power supply and the position of the rotary switch must remain unchanged! Then cover the cuvette again with the lid and measure the voltage U. For the transmission T in percent the value is T = U / U0 * 100. To get the absorption coefficient A you just have to calculate A = 100 - T.

I bought the different colored LEDs from Roithner Lasertechnik which is located in austria, my home country. For these, the respective wavelength is given in nanometers. To be really sure one can check the dominant wavelength with a spectroscope and the Theremino software (theremino spectrometer). In my case, the data in nm agreed with the measurements quite good. When selecting the LEDs, you should achieve as even coverage of the wavelength range from 395nm to 850nm.

For the first experiment with the photometer I chose chlorophyll. But for this you’ll have to pluck grass from a meadow hoping that no one is watching you ...

This grass is then cut into small pieces and put together with propanol or ethanol in a pot. Now you crush the leaves with a mortar or a fork. After a few minutes, the chlorophyll has dissolved nicely in the propanol. This solution is still too strong. It needs to be diluted with sufficient propanol. And to avoid any suspended the solution has to be filtered. I took a common coffee-filter.

The result should look like as shown in the picture. A very translucent green-yellowish solution. Then you repeat the measurement (U0, U) with each LED. As it can be seen from the obtained absorption curve, theory and measurement agree quite well. Chlorophyll a + b absorbs very strongly in the blue and red spectral range, while green-yellow and infrared light can penetrate the solution almost unhindered. In the infrared range, the absorption is even close to zero.

Step 4: Second Experiment: the Dependence of the Extinction on the Concentration of Potassium Permanganate

As a further experiment, the determination of the extinction depending on
the concentration of the solute offers. As a solute, I use potassium permanganate. The light intensity after penetrating the solution follows the Lambert-Beer law: It reads I = I0 * 10 ^ (- E). I0 is the intensity without solute, I the intensity with solute and E the so-called extinction. This extinction E depends (linearly) on the thickness x of the cuvette and on the concentration c of the solute. Thus, E = k * c * x with k as the molar absorption coefficient. To determine the extinction E you just need I and I0, because E = lg (I0 / I). When the intensity is reduced to, for example, 10%, the extinction E = 1 (10 ^ -1). With a weakening to only 1%, E = 2 (10 ^ -2).

If one applies E as a function of the concentration c, we would expect to obtain a rising straight line through the zero point.

As you can see from my extinction curve, it is not linear. At higher concentrations, it flattens, specifically from concentrations greater than 0.25. This means that the extinction is lower than would be expected according to the Lambert-Beer law. However, considering only lower concentrations, for example between 0 and 0.25, results in a very nice linear relationship between the concentration c and the extinction E. In this range, the unknown concentration c can be determined from the measured extinction E. In my case, the concentration has only arbitrary units, since I have not determined the initial amount of dissolved potassium permanganate (it has been only milligrams, which couldn’t be measured with my kitchen-scale in my case, dissolved in 4 ml water for the starting solution).

Step 5: Conclusions

This photometer is particularly suitable for physics and chemistry lessons.
The total cost is only around 60 Euro = 70 USD. The different colored LEDs are the most expensive part. On ebay or aliexpress you will certainly find cheaper LEDs but usually you do not know which wavelengths the LEDs have. Seen in this way, purchasing from a specialist retailer is recommended.

In this lesson you learn something about the relation between the colour of liquids and their absorption-behavior, about the important Chlorophyll, the Lambert-Beer law, exponentials, transmission and absorption, calculation of percents and the wavelengths of the visible colours. I think this is quite a lot...

So have fun also making this project in your lesson and Eureka!

Last but not least I'd be very happy if you could vote for me in the classroom-science-contest. Thank's for that...

And if you are interested in further physics experiments, here's my youtube-channel:

https://www.youtube.com/user/stopperl16/videos?

Classroom Science Contest

This is an entry in the
Classroom Science Contest

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    12 Discussions

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    umberto0560

    5 weeks ago

    Hello. Very nice job. As you wrote RGB are just three wavelength LEDs, and colors we see are just a perception. Which colors (or wavelength, it's better) do you advice to use?

    2 replies
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    stoppi71umberto0560

    Reply 5 weeks ago

    Hi! You can see those LEDs I'm using for this photometer in the pictures. I've bought them from Roithner Lasertechnik, located in vienna (austria). With those LEDs I cover the whole spectrum from 400nm to 850nm well. I tried to have just 20-30nm gaps between the wavelengths. On ebay you get 850nm IR, 395nm UV and some others. But f.e. I haven't found 5mm LEDs with lambda between 660 and 760nm. For these LEDs a Laser-LED-company would be the right choice. There are some companies like Roithner Lasertechnik in the USA for sure...

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    umberto0560stoppi71

    Reply 5 weeks ago

    Thank you for your advice. Since I'm in Italy, Austria should be my best choice. Of course you got my vote. Keep going on this way.

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    billbillt

    5 weeks ago

    A GREAT JOB.. THANKS FOR SHARING.. GOT MY VOTE!..

    1 reply
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    WalidElSharoud

    5 weeks ago

    Very nice project indeed. It will be very helpful if you may be able to demonstrate it on Youtube!!

    1 reply
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    stoppi71WalidElSharoud

    Reply 5 weeks ago

    Hello! You can see the way how to use it on youtube, just look at the video at the end...

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    JonS4

    5 weeks ago

    Nice project.

    Rather than use a series of different LEDs would it not be possible to drive an RGB LED from your Arduino and have the Arduino run the single diode through the entire color scale?

    2 replies
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    KdemonJonS4

    Reply 5 weeks ago

    I think the quality of the wavelength for RGBw are not as precise.

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    stoppi71Kdemon

    Reply 5 weeks ago

    Hi! When you use a RGB-Led you don't have different wavelengths even when the color changes. For example when the red and green led are on, then you get a yellow but no yellow wavelength. Therefore it isn't meaningful to use a RGB-Led. Better than so many different LEDs would be a continuous spectrum, which you would get with a monochromator consisting of a white light source, a f.e. Diffraction grating and slits. But on the other hand the light intensity of each wavelength would be much lower then my different LEDs and the setup would be more complicated