Introduction: LED'S on 220V AC GRID 7-8 WATTS ONLY

About: student of electrical engineering.

IN THIS INSTRUCTABLE I WILL TELL U HOW TO MAHE AN EFFICIENT LIGHT CONSISTS OF LED'S THAT ARE COMMONLY RUN ON DC CIRCUIT.
HERE IT WILL WORK ON 220 V AC FROM GRID
POWER CONSUMPTION IS 7 TO 8 WATT
AND ITS TRANSFORMER LESS.

COMPONENTS:
• Capacitors 2× 0.47uF 275v AC
• Capacitor 1× 10uF 400v AC
• Resistor 1× 10Ω 0.25W
• Resistor 1× 1MΩ 0.25W
• Fuse with holder 1×200ma
• 50×Led’s white 5mm

Hardware and tools required:
• Cable Duct 25×16mm
• Hand hack saw
• Soldering iron
• Drill machine
• Wire cutter
• Steel ruler
• marker
DRILL BIT ACORDING TO LED SIZE

Step 1: STEP 1

1. Get a duct and cut a small piece for 50 led’s depending on design and shape

Step 2: STEP 2

2. Remove its cover

Step 3: STEP 3

 Mark drill Points with marker and steel ruler

Step 4: STEP 4

 Drill Holes on marked points

Step 5: STEP 5

5. Place Led’s in each hole

Step 6: STEP 6

6. Solder led’s all in series

Step 7: STEP 7

7. Solder all other components according to circuit diagram and place them in bottom of duct use 200mA Fuse instead of 1A as in circuit.

Step 8: STEP 8

RUN THE CIRCUIT.

BECAREFULL WHILE USING 220V ITS DANGEROUS IF U ARE NOT PROFFESIONAL
I AM NOT RESPONSABLE FOR ANY DAMAGE .

Instructables Green Design Contest

Participated in the
Instructables Green Design Contest