# Line slope calculator x+4y=30

**Straight line given by points A[6; 6] and B[10; 5]**

## Calculation:

**Slope-intercept form of line:**y = -0.25x+7.5

**Canonical form of the line equation:**x+4y-30 = 0

**Parametric form of the line equation:**

x = 4t+6

y = -t+6 ; t ∈ R

**Slope:**m = -0.25

**Slope angle of line: φ =**-14°2'10″ = -0.245 rad

**X intercept:**x

_{0}= 30

**Y intercept:**y

_{0}= q = 7.5

**Distance line from the origin:**d

_{0}= 7.2761

**The length of the segment AB: |AB| =**4.1231

**Vector: AB =**(4; -1)

**Normal vector: n =**(1; 4)

**Midpoint of the segment AB: M =**[8; 5.5]

**Perpendicular Bisector equation:**4x-y-26.5 = 0

**Vector OA = (6; 6) ; |OA| = 8.4853**

**Vector OB = (10; 5) ; |OB| = 11.1803**

**Scalar product OA .OB = 90**

**Angle ∠ AOB = 18°26'6″ = 0.3218 rad**