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Two points :1) You don't need an extra diode (1N4007) as mentioned, since the LED itself will do the rectification.2) The Resistance should be 2 watts since the wattage drop across the resistor in that range, not because this is connected to AC. You can use a 1/4W resistor very well in ac if the current flow is limited further (by using higher value resistance). You can calculate the power drop across the resistor using the equation P = V^2/R = 230^2 / 22k = 2.4W. See that the power drop is more than 2W. To be on the safe side, use two resistors of 11K each and rated 2W each, in series, so that the power drop across each of them will be only 1.2W and hence lower than their rated dissipation.
Hello there.. Can anyone help me to make this circuit respond to high frequency? I got it working okay till 3kHz. I need it to work with a 32kHz frequency. Which component should be swapped for making work at such a frequency?
It depends on the current carrying capacity of the bridge and the mosfet. For example, if you need to control a 1000W load, the Mosfet and diodes in the bridge should carry atleast 5 Amps (1000W divided by 230V) of current. You can upgrade the circuit with higher current diodes and MOSFETs to achieve this.
I bet you are from my country !