358,66614
Industrial electrician with a keen interest in exploring all sorts of control and automation systems. Still teaching myself the basics of digital electronic circuit design. Huge fan of fast, cheap prototype iteration for the hobbiest thanks to our friends over in in the great PRC. Our future depends on how creative we can be...
MildLeeInterested's instructables
Achievements
10K+
Views
Earned a bronze medal
- MildLeeInterested commented on lonesoulsurfer's instructable Fizzle Loop Synth V3 (555 Timer)17 days ago
- MildLeeInterested commented on lonesoulsurfer's instructable Fizzle Loop Synth V3 (555 Timer)18 days ago
View Instructable »Cool. Thanks. I'm glad that my understanding of the ciruit was good enough to see the problem. I'm planning on designing a PCB for your circuit if I do, I'll make sure the gerber files are freely available.
- MildLeeInterested commented on lonesoulsurfer's instructable Fizzle Loop Synth V3 (555 Timer)19 days agoView Instructable »
Hi. Your schematic shows pins 2, 6 and 7 on IC3 all connected together. Is that right?
- MildLeeInterested commented on MildLeeInterested's instructable Program PIC with Arduino3 years agoView Instructable »
Hi RakeshA5,Not sure what you mean. All the Arduino connections, circuit diagrams, code, etc is documented on Rhys's website. There is a link in the text, but here it is again: http://rweather.github.io/ardpicprog/
Sorry, but that is not what the schematic shows. BertH11 is right - the schematic shows this resistor and switch shorted. Pushing the switch in the schematic won't do anything. The fact that this push button is doing something in your circuit proves that the schematic must be wrong, sorry.The pushbutton is (I think) normally closed. If so, it should be accros the resistor. If that were the case, it would be as you say - pushing the button would open the switch and put the resistor into the circuit, but that is NOT what the schematic shows.Sorry, I'm not meaning to pick fault. I'm just really keen to build this and want to have the circuit right.