# Line slope calculator 10x-3y=10

**Straight line given by points A[1; 0] and B[4; 10]**

## Calculation:

**Slope-intercept form of line:**y = 3.3333x-3.3333

**Canonical form of the line equation:**10x-3y-10 = 0

**Parametric form of the line equation:**

x = 3t+1

y = 10t ; t ∈ R

**Slope:**m = 3.3333

**Slope angle of line: φ =**73°18'3″ = 1.2793 rad

**X intercept:**x

_{0}= 1

**Y intercept:**y

_{0}= q = -3.3333

**Distance line from the origin:**d

_{0}= 0.9578

**The length of the segment AB: |AB| =**10.4403

**Vector: AB =**(3; 10)

**Normal vector: n =**(10; -3)

**Midpoint of the segment AB: M =**[2.5; 5]

**Perpendicular Bisector equation:**3x+10y-57.5 = 0

**Vector OA = (1; 0) ; |OA| = 1**

**Vector OB = (4; 10) ; |OB| = 10.7703**

**Scalar product OA .OB = 4**

**Angle ∠ AOB = 68°11'55″ = 1.1903 rad**