Universal Logic Gates Implementer With Arduino

13,689

13

8

Introduction: Universal Logic Gates Implementer With Arduino

About: An Electrical Engineering Teacher in Athens Greece. Most of these small projects here, are constructed for enhancing the learning of the use of Arduino as well as basic electricity and electronics for students…

This was build as a teaching aid for electricians and electronic technicians.
Students will look up on the code how it was built, and then simply will
confirm the output of the basic logic gates or even make combinations of them,
There are 3 inputs (you can add more for your needs) so there is much more to test then just confirming the gates.
In the code are the comments to explain its functions. Have fun!

(P.S. this could little program could have futher improvment, suggestions are welcomed!)

Supplies:

Two (2) buttons
1 LED
1 Resistor 330Ω (Or any kind of these typical prices 150, 220, 270, 330, 470, 560Ω)

Step 1: The Code

/********************************
* Universal Logic Gates Implementer with Arduino
* Created by Panos Agiakatsikas
* Date: 22/1/2017
*******************************
The logic gates
Buffer A (Also(!A&&!A)) output [0]
NOT !A output [1]
AND (A&&B) output [0001]
OR (A||B) output [0111]
NAND (!(A&&B)) output [1110]
NOR (!(A||B) output [1000]
XOR (!A&&B)||(A&&!B) output [0110]
XNOR (A&&B)||(!A&&!B) output [1001]
*/

int buttonPin1 = 2; // Button 1
int buttonPin2 = 3; // Button 2
int buttonPin3 = 4; // Button 3
int LEDred = 13; // Out to pin

int A; // variable for input state of the button 1
int B; // variable for input state of the button 2
int C; // variable for input state of the button 3

void setup() {
pinMode(LEDred, OUTPUT); // set led as output
// set pins as inputs with internal pull-up resistor, the open button logic state for all will be HIGH
pinMode(buttonPin1, INPUT_PULLUP);
pinMode(buttonPin2, INPUT_PULLUP);
pinMode(buttonPin3, INPUT_PULLUP);
}

void loop(){
A = digitalRead(buttonPin1);
B = digitalRead(buttonPin2);
C = digitalRead(buttonPin3);

A=!A; // inverse the HIGH to LOW from the pull-up resistor
B=!B; // inverse the HIGH to LOW from the pull-up resistor
C=!C; // inverse the HIGH to LOW from the pull-up resistor

if (!(A||B)) { // put here your logic statement
digitalWrite(LEDred, HIGH);
} else {
digitalWrite(LEDred, LOW);
}
}

Step 2: How It Works: Example A

Lets say you want to test the AND Gate
In the code and the if statetment simply put the AND statement (A&&B), you must apply the truth table like this pressing the buttons an input A and B
the output Y will be on the LED [0001]
A | B | Y
0 | 0 | 0
1 | 0 | 0
0 | 1 | 0
1 | 1 | 1

Step 3: Example B

Now lets say we want to find out what is the output of the above. We must figure out the logic combinational statement here that is (!A&&B)||(A&&!B) and again insert in the if statement in the code Try it!
the output is [0110]

Step 4: Example C

Τhis simple example has 3 inputs. We write here the boolean expression as ((A&&B)&&C)).The output y result will be like the array, and only when the 3 buttons are press simultaneously we will have the LED on.

Step 5: Example D

One more example. The picture say it clear (A||B)&&(A||C).
If you try this. the output should be

Y = [00011111]

Be the First to Share

    Recommendations

    • Make it Glow Contest

      Make it Glow Contest
    • First Time Author Contest

      First Time Author Contest
    • PCB Challenge

      PCB Challenge

    8 Discussions

    1
    StephenB252
    StephenB252

    10 months ago

    This is great but at the moment it is not working for me, I think I am going to strip back and just create a single input based on your AND and OR tutorials, but great resource, thanks!

    1
    iamstephenburrows
    iamstephenburrows

    Reply 10 months ago

    Hi I worked out why it would not work for me. In the fritzing diagram, the LED output is placed in slot 13. But in the code the LED output should be in slot 8. I changed this and it works perfectly.
    Thanks so much, such a great program to help students simplify complex boolean expression.

    0
    PanosA6
    PanosA6

    Reply 9 months ago

    Correct thank you for debugging!

    0
    Jencek
    Jencek

    2 years ago

    THX.. It helped me a lot for my project.. SUPER..!

    0
    saichandrareddy9459
    saichandrareddy9459

    Reply 1 year ago

    Bruh, could you tell wat value resistor is used in this project...........?

    0
    PanosA6
    PanosA6

    Reply 10 months ago

    330Ω