Universal Logic Gates Implementer With Arduino

Intro: Universal Logic Gates Implementer With Arduino

This was build as a teaching aid for electricians and electronic technicians.
Students will look up on the code how it was built, and then simply will
confirm the output of the basic logic gates or even make combinations of them,
There are 3 inputs (you can add more for your needs) so there is much more to test then just confirming the gates.
In the code are the comments to explain its functions. Have fun!

(P.S. this could little program could have futher improvment, suggestions are welcomed!)

STEP 1: The Code

/********************************
* Universal Logic Gates Implementer with Arduino
* Created by Panos Agiakatsikas
* Date: 22/1/2017
*******************************
The logic gates
Buffer A (Also(!A&&!A)) output [0]
NOT !A output [1]
AND (A&&B) output [0001]
OR (A||B) output [0111]
NAND (!(A&&B)) output [1110]
NOR (!(A||B) output [1000]
XOR (!A&&B)||(A&&!B) output [0110]
XNOR (A&&B)||(!A&&!B) output [1001]
*/

int buttonPin1 = 2; // Button 1
int buttonPin2 = 3; // Button 2
int buttonPin3 = 4; // Button 3
int LEDred = 13; // Out to pin

int A; // variable for input state of the button 1
int B; // variable for input state of the button 2
int C; // variable for input state of the button 3

void setup() {
pinMode(LEDred, OUTPUT); // set led as output
// set pins as inputs with internal pull-up resistor, the open button logic state for all will be HIGH
pinMode(buttonPin1, INPUT_PULLUP);
pinMode(buttonPin2, INPUT_PULLUP);
pinMode(buttonPin3, INPUT_PULLUP);
}

void loop(){
A = digitalRead(buttonPin1);
B = digitalRead(buttonPin2);
C = digitalRead(buttonPin3);

A=!A; // inverse the HIGH to LOW from the pull-up resistor
B=!B; // inverse the HIGH to LOW from the pull-up resistor
C=!C; // inverse the HIGH to LOW from the pull-up resistor

if (!(A||B)) { // put here your logic statement
digitalWrite(LEDred, HIGH);
} else {
digitalWrite(LEDred, LOW);
}
}

STEP 2: How It Works: Example A

Lets say you want to test the AND Gate
In the code and the if statetment simply put the AND statement (A&&B), you must apply the truth table like this pressing the buttons an input A and B
the output Y will be on the LED [0001]
A | B | Y
0 | 0 | 0
1 | 0 | 0
0 | 1 | 0
1 | 1 | 1

STEP 3: Example B

Now lets say we want to find out what is the output of the above. We must figure out the logic combinational statement here that is (!A&&B)||(A&&!B) and again insert in the if statement in the code Try it!
the output is [0110]

STEP 4: Example C

Τhis simple example has 3 inputs. We write here the boolean expression as ((A&&B)&&C)).The output y result will be like the array, and only when the 3 buttons are press simultaneously we will have the LED on.

STEP 5: Example D

One more example. The picture say it clear (A||B)&&(A||C).
If you try this. the output should be

Y = [00011111]

Comments

[StephenB252]

This is great but at the moment it is not working for me, I think I am going to strip back and just create a single input based on your AND and OR tutorials, but great resource, thanks!

[iamstephenburrows]

Hi I worked out why it would not work for me. In the fritzing diagram, the LED output is placed in slot 13. But in the code the LED output should be in slot 8. I changed this and it works perfectly.
Thanks so much, such a great program to help students simplify complex boolean expression.

[PanosA6]

Correct thank you for debugging!

[Jencek]

THX.. It helped me a lot for my project.. SUPER..!

[saichandrareddy9459]

Bruh, could you tell wat value resistor is used in this project...........?

[PanosA6]

330Ω

[StephenB252]

3 reds = 100 ohm, check this https://learn.parallax.com/support/reference/resistor-color-codes

[saichandrareddy9459]

what was the resistor value used.............?