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# How many peltier module i have to use for removing heat load of 250 watt? Answered

i am using peltier modules  12706   ( vmax  15 v, Imax  6 A)               by checking it was running at   12 v  and 3.5 A

and   peltier module 12715  ( Vmax  15V ,  I max  15 A )           was  running at  12 v  and 5.5 A

I am using computer SMPS to run this peltiers so i can only get 12 v max
is there any way to increase voltage to 15 volt.

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i am using total 8 peltier module

4 module running at 12v at 5.5a == 264w

4 module running at 12v at 3,5 a == 164 w

total = 428 w considering cop 0.5 it will transfer 214 w i think so.

correct me if i am wrong..

Where are you transferring the heat ? A 100W module, which might handle a 50 Deg delta T will only move 50W, with a delta T of 25 degrees. It can create a 50 deg delta T, with NO heat flow, or it can create a 100W heatflow with no deltaT

A peltier module doesn't remove heat, it transports it from one side to the other - while generating even more heat! You have to find a way to get rid of all this combined heat on the hot side of the module.

Hello Yogesh,

First of all 15V is Vmax. That doesn't mean that you need to supply 15V. 12V is also sufficient.

Now to calculate no. of modules-

Datasheet for 12706

http://www.thermonamic.com/TEC1-12706-English.PDF

Datasheet for 12715

http://www.thermonamic.com/TEC1-12715-English.PDF

These datasheets I found on google. To calculate heat transfer per module.

Consider Voltage applied, Current supplied, Temperature difference and using graphs in the datasheets, you can get watt per module.

[ 250 / watt heat removed per module ] will give you no. of modules required.

(In datasheet it is written Qc / W , that means Qc = heat flow and W = watt ie. unit) because i too confused first time.

Don't forget, you trade off power handling for temperature difference.